Question

<?php
    $ts='2011-04-13 23:00:00';
    $ts1='2011-04-14 15:45:00';
    echo $addtime = date("h:i:s", mktime(date("h", $ts1)- date("h", $ts),date("i", $ts1)- date("i", $ts),date("s", $ts1)- date("s", $ts),0,0,0));
?>

它给出了结果但在许多情况下它是不正确的。我该如何解决？

Answer 1

对于给定的示例，您的预期结果将是16:45:00，对吗？因此，您希望两个给定日期之间的差异以小时为单位：分钟：秒。

<?php
    //initial strings
    $ts='2011-04-13 23:00:00'; 
    $ts1='2011-04-14 15:45:00';

    //converting to time
    $start = strtotime($ts);
    $end = strtotime($ts1);

    //calculating the difference
    $difference = $end - $start;

    //calculating hours, minutes and seconds (as floating point values)
    $hours = $difference / 3600; //one hour has 3600 seconds
    $minutes = ($hours - floor($hours)) * 60;
    $seconds = ($minutes - floor($minutes)) * 60;

    //formatting hours, minutes and seconds
    $final_hours = floor($hours);
    $final_minutes = floor($minutes);
    $final_seconds = floor($seconds);

    //output
    echo $final_hours . ":" . $final_minutes . ":" . $final_seconds;
?>

这给了我正确的结果。希望我的问题正确！

想要从两个日期之间减去小时到小时，分钟到分钟以及秒到秒

1 个答案: