Question

我有一个类似

的列

2014.STA.?
2014.STA.?
2014.STA.?
2015.STA.?
2016.STA.?
2014.STA.?
2014.STA.?
2016.STA.?

我需要创建一个我可以按年分组并添加索引而不是“？”的函数。这意味着，我希望得到像这样的结果

2014.STA.1
2014.STA.2
2014.STA.3
2015.STA.1
2016.STA.1
2014.STA.4
2014.STA.5
2016.STA.2

我不知道如何对这些列进行格式化并在函数中使用它。

for mssql2008

Answer 1

使用Row_Number窗口函数生成数字

select left(yourcol,len(yourcol)-1)+cast(RN as varchar(20)) 
(
select row_number()over(partition by your_col order yourcol) As RN,*
From yourtable
)

Answer 2

我认为这可以满足您的需求：

select (left(col, 9) +
        cast(row_number() over (partition by left(col, 9) order by (select null)) as varchar(255))
       )

注意：这会对值进行任意排序。据推测，有一个列指定了数字的正确排序。

实际上，您可以使用cast()

在没有replace()的情况下执行此操作

select replace(col, '?', 
               row_number() over (partition by left(col, 9) order by (select NULL))
              )

此版本中隐含cast()。

Answer 3

select substring(c1, 1, 9) + CONVERT(CHAR, ROW_NUMBER() OVER (partition by c1 ORDER BY substring(c1,1,4)))  from @tabla

它适用于我的SQL Server 2014.请检查：

select substring(c1, 1, 9) + cast(ROW_NUMBER() OVER (partition by c1 ORDER BY substring(c1,1,4)) as char(12))  from @tabla

如果你想按号码订购：

select r1 from (
select substring(c1, 1, 9) + cast(ROW_NUMBER() OVER (partition by c1 ORDER BY substring(c1,1,4)) as char(12)) AS r1 from @tabla) AS T
order by substring(r1, 10, len(r1))

SQL增量计数器

3 个答案: