MS SQL从另一个表中按行复制数据

Question

我有以下2个表：

DECLARE @table1 TABLE (
    [NO] int,
    A1 float, 
    A2 float, 
    A3 float, 
    A4 float, 
    A5 float,
    A6 float
)

DECLARE @table2 TABLE (
    KOD nvarchar(100), 
    ID_QUANTITY int
)

INSERT INTO @table1 VALUES
(1, 4.1, 3, 3.5, 23.5, 12.2, 2.4),
(2, 4.2, 0, 1.9, 34.5, 31.2, 34.2),
(3, 1.5, 0, 2.3, 12.3, 12.3, 1.2),
(4, 3.7, 2.1, 5.9, 4.8, 10.2, 21.2),
(5, 3.9, 2.6, 1.9, 12.3, 2.4, 10.2)

INSERT INTO @table2 VALUES
('A1', 500),
('A2', 600),
('A3', 700),
('A4', 800),
('A5', 900),
('A6', 1000)

我需要在sql中创建脚本，将第一个表中的变换值变为外观，如下所示

感谢您的帮助

Answer 1

UNPIVOT然后加入，对ID列使用ROW_NUMBER（）：

SELECT  ROW_NUMBER() OVER (ORDER BY (SELECT 1)) as ID,
        ID_QUANTITY,
        [VALUES]
FROM (
    SELECT *
    FROM table1
    ) p
UNPIVOT (
    [VALUES] FOR [COL] IN (A1,A2,A3,A4,A5,A6)
) as unpvt
LEFT JOIN table2 t 
    ON t.KOD = unpvt.[COL]
ORDER BY ID_QUANTITY, [NO]

输出：

ID  ID_QUANTITY VALUES
1   500         4,1
2   500         4,2
3   500         1,5
4   500         3,7
5   500         3,9
6   600         3
7   600         0
8   600         0
9   600         2,1
10  600         2,6
...
25  900         2,4
26  1000        2,4
27  1000        34,2
28  1000        1,2
29  1000        21,2
30  1000        10,2

Answer 2

使用UNPIVOT

SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)),
    t2.ID_Quantity,
    t1.Value 
FROM Table2 t2
INNER JOIN 
(
            SELECT * 
            FROM Table1
            UNPIVOT 
            (
                [Values] FOR [Columns] IN ([A1], [A2],[A3], [A4], [A5],[A6])
            ) as pvt
) t1
ON t1.Columns = t2.KOD

Answer 3

试试这个：

create table3（ID_QUANTITY int（11），VALUE int（11））;

for($i=1;$i<6;$i++){ $insert=mysql_query("insert into table3 select a.ID_QUANTITY,b.A$i from table2 a,table1 b where a.KOD='A$i'); }