Question

如果我有两张桌子，

首先table1：

id   name

1    John
2    Andrew
3    Serj
4    Mike
5    Adam

和第二个table2：

 user_id  count  date

  2       0      01-09-2011...
  5       9      05-09-2011...
  1       5      05-09-2011...
  3       7      04-09-2011...

如何从table1中选择用户，并按count，date table2来自1 -- Adam ( count = 9 , date = 05.. ) 2 -- John ( count = 5 , date = 05.. ) 3 -- Serj ( count = 7 , date = 04.. ) 4 ... 5 ... ...（DESC）

的值进行排序

我想要的结果：

{{1}}

如果无法实现，或者难以获得我想要的结果（请参阅我的结果），那么只需按计数和日期排序。

Answer 1

select * from table1 t1 
join table2 t2 on t1.id = t2.user_id 
order by date desc, count desc

Answer 2

使用JOIN。

SELECT name from table1
JOIN table2 ON table1.id = table2.user_id
ORDER BY table2.count, table2.date DESC

Answer 3

请试试

select * from table1 t1 
join table2 t2 on t1.id = t2.user_id 
order by date, count desc

Answer 4

使用INNER JOIN

   SELECT t1.name, t2.count, t2.date
   FROM table1 AS t1 INNER JOIN table2 AS t2 
   ON t1.id = t2.user_id
   ORDER BY t2.count DESC, t2.date DESC;

按另一个表中的数据排序行

4 个答案: