如何将python使用者脚本附加到特定的kafka分区。
在运行两个消费者脚本实例(如下所示)时,每个实例随机选择一个分区,然后消耗/打印该特定分区的所有消息,如预期的那样。
但是,由于我需要将这些消息输出到磁盘上名为本地文件的分区,因此将每个脚本实例附加到预先声明的分区ID会使事情变得更容易。
文件名例如。 :
Date/Hour/PARTITION_ID-0.CSV
Date/Hour/PARTITION_ID-1.CSV
关于如何实现这一目标的任何想法。
随意建议替代方法。
Kafka设置:
Topic:my-topic3 PartitionCount:2 ReplicationFactor:2 Configs:
Topic: my-topic3 Partition: 0 Leader: 2 Replicas: 2,1 Isr: 2,1
Topic: my-topic3 Partition: 1 Leader: 1 Replicas: 1,2 Isr: 1,2
Kafka Consumer Script(在python中)[ WITH FIX ]
from kafka import KafkaConsumer
from kafka import TopicPartition
# To consume latest messages and auto-commit offsets
#consumer = KafkaConsumer('my-topic3',
# group_id='my-group',
# bootstrap_servers=['192.168.150.80:9092'])
# To consume messages from a specific PARTITION [ FIX ]
consumer = KafkaConsumer(bootstrap_servers='192.168.150.80:9092')
consumer.assign([TopicPartition('my-topic3', 1)])
for message in consumer:
# message value and key are raw bytes -- decode if necessary!
# e.g., for unicode: `message.value.decode('utf-8')`
print ("Topic= %s : Partition= %d : Offset= %d: key= %s value= %s" % (message.topic, message.partition,
message.offset, message.key,
message.value))
更新:如下所示,我使用了assign函数,但一直收到非法状态错误 分配功能
consumer.assign([TopicPartition('my-topic3',1)])
错误
Traceback (most recent call last):
File "consumerExample.py", line 13, in <module>
consumer.assign([TopicPartition('my-topic3',1)])
File "/usr/lib/python2.7/site-packages/kafka/consumer/group.py", line 278, in assign
self._subscription.assign_from_user(partitions)
File "/usr/lib/python2.7/site-packages/kafka/consumer/subscription_state.py", line 189, in assign_from_user
raise IllegalStateError(self._SUBSCRIPTION_EXCEPTION_MESSAGE)
kafka.errors.IllegalStateError: You must choose only one way to configure
答案 0 :(得分:0)
You can use the assign()
method手动为消费者分配一个或多个分区。
>>> # manually assign the partition list for the consumer
>>> from kafka import TopicPartition
>>> consumer = KafkaConsumer(bootstrap_servers='localhost:1234')
>>> consumer.assign([TopicPartition('foobar', 2)])
>>> msg = next(consumer)