Question

要求摘要：
每当客户输入新订单时，在旧订单前检查信用卡信息和使用代码。如果有不同的客户使用相同的信用卡，则该信息将输入新表以验证客户数据

我面临的问题：
问题是同一客户和同一信贷的条件不起作用......

我尝试了什么：

CREATE TRIGGER order_credit_card
ON dbo.orders
FOR INSERT
AS
    DECLARE @O_ID VARCHAR (20)
    DECLARE @O_Date Datetime
    DECLARE @O_Made_By VARCHAR (255)
    DECLARE @O_Credit VARCHAR(50)
    BEGIN
        IF CURSOR_STATUS('global','Credit_Card_CURSOR')>=-1
        BEGIN
            DEALLOCATE Credit_Card_CURSOR
        END

        DECLARE Credit_Card_CURSOR CURSOR FOR
            SELECT [order-id], [date], [made-by], [paid-with]
            FROM inserted

        OPEN Credit_Card_CURSOR

        FETCH NEXT FROM Credit_Card_CURSOR INTO @O_ID, @O_Date, @O_Made_By, @O_Credit
        WHILE (@@FETCH_STATUS = 0)
        BEGIN
            IF @O_Made_By IN (SELECT o.[Made-by]
                              FROM Orders o
                              WHERE o.[Made-by] = @O_Made_By 
                                AND o.[paid-with] = @O_Credit)
            BEGIN
                UPDATE DBO.orders
                SET [approved] = 'ok'
                WHERE [Made-by] = @O_Made_By
            END
            ELSE
            BEGIN
                INSERT INTO DBO.[Security_warrnings]
                VALUES (@O_ID, @O_Credit) 
            END

        FETCH NEXT FROM Credit_Card_CURSOR INTO @O_ID, @O_Date, @O_Made_By, @O_Credit
    END

    CLOSE Credit_Card_CURSOR 
END

Answer 1

您不需要光标。您可以使用Inserted虚拟表...根据您的要求进行修改。如果客户已使用相同的信用卡号进行购买，则代码会将数据插入到其他表中。

Create trigger dbo.test
on yourtable
after insert 
as
Begin
--check if user has made purchase with same CC number
if exists
(select 1 from 
 from 
Orders   o
join
inserted i
on i.O_Made_By =o.O_Made_By 
and i.creditcardnumber=o.creditcardnumber
)
Begin
--he made 
insert into DBO.[Security_warrnings]
select i.orderid,i.creditcardnumber
from inserted i
join
yoursordertable o
on o.creditcardnumber=i.creditcardnumber

End

End

Answer 2

CREATE TRIGGER order_credit_card
...
BEGIN
    declare @orders_with_warning table ([order-id] int)

    insert into DBO.[Security_warrnings] ([order-id], [paid-with])
        OUTPUT INSERTED.id
        INTO @orders_with_warning([order-id])
    select i.[order-id], i.[paid-with]
    from inserted i
    where exists(select 1 from dbo.Orders o
        where o.[paid-with] = i.[paid-with]
            and o.[Made-by] != i.[Made-by])

    UPDATE o SET
        [approved]= 'ok'
    from DBO.orders o
    inner join inserted i
    on i.[order-id] = o.[order-id]
    where not exists(select 1 from @orders_with_warning ow
        where ow.[order-id] = o.[order-id])
END

尝试：

@O_Made_By in (select  o.[Made-by]
                      from Orders  o
                      where o.[Made-by]=@O_Made_By

实际上毫无意义。将col / var name替换为number以检查方案：

23 in (select 23 where 23=23)

SQL Server，使用游标

2 个答案: