Question

我有一个名单，其中包含一个支票帐户和/或一个与其直接存款相关联的储蓄帐户。 22表示检查，32表示节省。

如果他们在列中只有一个支票帐户（22）或只有一个储蓄帐户（32），那么我希望在其旁边的列中有一个'100％'。但是，如果一个人有支票和储蓄账户，我想留空。（我们必须手动查看其他软件以获取信息）

实施例

Employee # Account Allocated % 100 22 100 32 101 22 100 102 32 100

我该怎么做？

Answer 1

我使用这样的东西：

UPDATE t1
SET [Allocated %] = 100
FROM YourTable t1
WHERE t1.Account IN (22,32)
    AND NOT EXISTS (
        SELECT 1
        FROM YourTable t2
        WHERE t2.[Employee #] = t1.[Employee #]
            AND t2.Account IN (22,32)
            AND t2.Account <> t1.Account
    )

但是，当然，您应该首先检查它是否正确：

SELECT *
FROM YourTable
WHERE YourTable.Account IN (22,32)
    AND YourTable.[Employee #] IN (
        SELECT t1.[Employee #]
        FROM YourTable t1
        WHERE t1.Account IN (22,32)
            AND NOT EXISTS (
                SELECT 1
                FROM YourTable t2
                WHERE t2.[Employee #] = t1.[Employee #]
                    AND t2.Account <> t1.Account
                    AND t2.Account IN (22,32)
            )
    )
ORDER BY [Employee #], Account;

Answer 2

您可以按员工＃进行分组，并使用一个标志来检查22和一个使用case语句检查32的标志。

测试场景

select *
into ##tempAccounts
from (
select EmployeeNum = 100, Account = 22
union all select EmployeeNum = 100, Account = 32
union all select EmployeeNum = 101, Account = 22
union all select EmployeeNum = 102, Account = 32
) x


select *  from ##tempAccounts


select 
    Accounts.EmployeeNum, 
    Accounts.Account,
    case when AccountStatHelper.Has22 = 1 and AccountStatHelper.Has32 = 1 then Null else '100%' end
from ##tempAccounts as Accounts
left join
(
    select
        EmployeeNum,
        Has22 = max(case when Account = 22 then 1 else 0 end),
        Has32 = max(case when Account = 32 then 1 else 0 end)
    from ##tempAccounts
    group by EmployeeNum
) AccountStatHelper on Accounts.EmployeeNum = AccountStatHelper.EmployeeNum


drop table ##tempAccounts

<强>结果

EmployeeNum Account     
----------- ----------- ----
100         22          NULL
100         32          NULL
101         22          100%
102         32          100%

Answer 3

一个真正简单的方法就是这样：

SELECT *, CASE WHEN 
    (SELECT COUNT(*) FROM Accounts WHERE EmpNo = A.EmpNo) = 1 
     THEN 100 ELSE NULL END AS Allocation FROM Accounts A

这不会检查22或32状态。它只是看他们是否有多种类型的帐户。这可能是最简单的方法，假设您的逻辑是他们有多个帐户，那么它需要为100。

这是sample fiddle。

检查具有两个属性的列

3 个答案: