Question

我想将画布线分割成相同大小Ls的多个部分。但在C＃中我只有可用线的坐标。对于点A = {x1, y1}和点B = {x2, y2}。现在我需要线的每个分离部分的坐标...

Answer 1

我们有N个部分和坐标差异

Dx = B.X - A.X
Dy = B.Y - A.Y

然后第i个分段结束的坐标是

P[i].X = A.X + i * Dx / N
P[i].Y = A.Y + i * Dy / N

Answer 2

假设一行<body ng-class='{"is-loading": isLoading }'>和A[x=0,y=0]分为3个子行

B[x=9,y=9]和A1[x=0,y=0]
B1[x=3,y=3]和A2[x=3,y=3]
B2[x=6,y=6]和A3[x=6,y=6]

您有两个班级：B3[x=9,y=9]由2 line s：

组成

point

用法：

public class point
{
    public double x { get; set; }
    public double y { get; set; }
}

public class line
{
    public point p1 { get; set; }
    public point p2 { get; set; }

    public line(point p1, point p2)
    {
        this.p1 = p1;
        this.p2 = p2;
    }

    public List<line> SplitLine(int parts)
    {
        List<point> result = new List<point>();
        for (int i = 0; i <= parts; i++)
        {
            result.Add(new point()
            {
                x = this.p1.x + (i * (this.p2.x - this.p1.x) / parts),
                y = this.p1.y + (i * (this.p2.y - this.p1.y) / parts)
            });
        }
        return Enumerable.Range(0, parts).Select(x => new line(result[x], result[x + 1])).ToList();
    }
}

C＃ - 分割线的坐标

2 个答案: