Question

有没有办法定义多个＆＃34;不等式约束＆＃34;在R？

的nloptr包中

不平等函数需要有五个不等式约束;矩阵的colsum（从整数向量堆叠）＆lt; = 1。（6列中的5列）

这是我实现它的方式：

 constraint.func <- function(my.data.var)
{
  column = 2
  constr <- c("numeric",ncol(my.data.matrix.inj) ) 

  for(index in 1:ncol(my.data.matrix.inj)) #1 to 5
  {
    constr[index] <- sum(my.data.var[column], my.data.var[column+6],  my.data.var[column+12], my.data.var[column+18])-1 
    column = column+1
  }
   constr.1 <- c(constr[1],constr[2],constr[3],constr[4],constr[5])

 return(constr.1)
}

my.data.var是数字向量，以矩阵形式堆叠。

my.data.var <- c(10,0.25,0.25,0.25,0.25,0.25,
             10,0.25,0.25,0.25,0.25,0.25,
             10,0.25,0.25,0.25,0.25,0.25,
             10,0.25,0.25,0.25,0.25,0.25)

my.data.var

NLOPTR定义如下，但是当我运行它时，它表示＆＃34;不等式约束的数量= 0＆＃34;。

  opts = list("algorithm"="NLOPT_LN_COBYLA",
            "xtol_rel"=1.0e-5, "maxeval"=500)

result <- nloptr(my.data.var,eval_f = Error.func,lb=c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0),
                 ub = (Inf,1,1,1,1,1,Inf,1,1,1,1,1,Inf,1,1,1,1,1,Inf,1,1,1,1,1),
           eval_g_ineq=constraint.func,opts = opts)

print(result)

更新的答案：我将Constraint.func定义为

constraint.func <- function(my.data.var)
{
  column = 2
  constr <- vector("numeric",length = 5)
  for(index in 1:ncol(my.data.matrix.inj))
  {
    constr[index] <- sum(my.data.var[column], my.data.var[column+6], my.data.var[column+12], my.data.var[column+18])-1
    column = column+1
  }
 return(constr)
}

Answer 1

我更新了 Constraint.func ，现在 nloptr 选择了不等式约束。

constraint.func <- function(my.data.var)
{
  column = 2
  constr <- vector("numeric",length = 5)

 for(index in 1:ncol(my.data.matrix.inj))
  {
    constr[index] <- sum(my.data.var[column], my.data.var[column+6], my.data.var[column+12], my.data.var[column+18])-1
    column = column+1
  }
 return(constr) }

Answer 2

我知道这已经晚了好几年了，但我最近也遇到了这个问题，似乎 eval_g_ineq 可以返回一个约束值向量：


library(nloptr)

# objective function
eval_f0 <- function( x, a, b ){return( sqrt(x[2]) )}

# constraint functions
eval_g0 <- function( x, a, b ) {
  
  g1 <- (a*x[1] + b)^3 - x[2] ^2
  g2 <- (a*x[1] + 2 * b)^3 - x[2]
  
  return( c(g1, g2) )
}

a <- c(2,-1)
b <- c(0, 1)
x0 <- c(1.234,5.678)

# Solve using NLOPT_LN_COBYLA without gradient information
res1 <- nloptr( x0=x0 ,
                eval_f=eval_f0,
                lb = c(-Inf,0),
                ub = c(Inf,Inf),
                eval_g_ineq = eval_g0,
                opts = list("algorithm" = "NLOPT_LN_COBYLA",
                            "xtol_rel" = 1e-8,
                            "maxeval" = 1e4,
                            "print_level" = 2),
                a = a, 
                b = b )
print( res1 )

＆＃34;多重不平等约束＆＃34; - 使用R nloptr包最小化

2 个答案: