Question

该应用程序运行，但一个特定的功能不会。每当我尝试登录或注册帐户时，Gradle控制台都会说它跳过了框架并且运行太多。我想要做的是接收用户信息并将其发送到数据库。这是存在问题的注册活动代码。如果我把JSON拿出来并且只是让新活动打开，那就可以了。

 Response.Listener<String> responseListener = new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    try {
                        JSONObject jsonResponse = new JSONObject(response);
                        boolean success = jsonResponse.getBoolean("success");
                        if (success) {
                            Intent intent = new Intent(RegisterActivity.this, LoginActivity.class);
                            RegisterActivity.this.startActivity(intent);
                        } else {
                            AlertDialog.Builder builder = new AlertDialog.Builder(RegisterActivity.this);
                            builder.setMessage("Register Failed")
                                    .setNegativeButton("Retry", null)
                                    .create()
                                    .show();
                        }
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                }
            };

            RegisterRequest registerRequest = new RegisterRequest(username, email, password, responseListener);
            RequestQueue queue = Volley.newRequestQueue(RegisterActivity.this);
            queue.add(registerRequest);
        }
    });
}
}

注册的Php代码：

 $username = $_POST["username"];
$email = $_POST["email"];
$password = $_POST["password"];

$statement = mysqli_prepare($con, "INSERT INTO data (username, email, password) VALUES (?, ?, ?, ?)");
mysqli_stmt_bind_param($statement, "sss", $username, $email, $password);
mysqli_stmt_execute($statement);

$response = array();
$response["success"] = true;  

echo json_encode($response);
?>

注册请求代码：

private Map<String, String> params;

public RegisterRequest(String username, String email, String password, Response.Listener<String> listener){
    /*
    NExt line means we are going to pass some information into the register.php
     */
    super(Method.POST, REGISTER_REQUEST_URL, listener, null);
    /*
    This is how we pass in the information from the register to the thing, we are using a hashmap
     */
    params = new HashMap<>();
    params.put("username", username);
    params.put("email", email);
    params.put("password", password);

}
/*
Volley needs to get the data so we do a get params
Which gives us this method
 */

@Override
public Map<String, String> getParams() {
    return params;
}
}

有谁知道我怎么解决这个???我不知道如何在此输入Async任务，如果有人可以，请帮忙。无论如何在没有异步任务的情况下解决这个问题？谢谢！

Answer 1

您可能正在主线程上运行网络请求，这是Android Framework用于呈现UI的线程。您需要使用某种机制在另一个线程上执行网络任务。 AsyncTask是最简单的实现方式，并且对您的方案有益，因为这是一项简单的任务。

扩展AsyncTask并将您的请求参数传递给Map：

public class RegisterTask extends AsyncTask<Map, Void, Boolean> {

    @Override
    protected Boolean doInBackground(Map... params) {
        Map props = params[0];  // you can access your request params here

        /*
         Do your network request here, using HttpUrlConnection or 
         HttpClient. and return a result (boolean in this example),
         which is passed to the onPostExecute method
        */
        return false;
    }

    @Override
    protected void onPostExecute(Boolean aBoolean) {
        // This method is run on the main thread, so you can
        // update your UI after the request is completed.
    }
}

您可以像这样执行此任务：

RegisterTask task = new RegisterTask();
task.execute(yourHashMapContainingData);

查看此官方Google文档以获取更多详细信息： Perform Network Operations on a Separate Thread

Android Studio App不会运行数据库

1 个答案: