Question

我正在尝试构建一个php函数，该函数将返回一个数组，其中包含最后n周的开始日期和结束日期。这将包括本周。它看起来像这样：

function lastnweeks(n)
{
//the code. I am not asking for the code itself but ideas on how to accomplish this
return $array; 
}
$lastnweeks =lastnweeks(2);
print_r($lastnweeks);

这会打印出来：

Array ( 
    [0] =>  Array ( 
        [0] => 2010/09/20 
        [1] => 2010/09/26
   )[1] => Array ( 
        [0] => 2010/09/13 
        [1] => 2010/09/19
))

Answer 1

由于夏令时和leapyears / leapseconds，我不会使用绝对秒数。你可以让PHP的strtotime()函数通过使用相对日期为你处理这个问题。通过循环的每次迭代，您只需告诉函数找到“上周一”，然后使用该结果作为下一次迭代的起点。

代码：

$past_weeks = 7;
$relative_time = time();
$weeks = array();

for($week_count=0;$week_count<$past_weeks;$week_count++) {
    $monday = strtotime("last Monday", $relative_time);
    $sunday = strtotime("Sunday", $monday);
    $weeks[] = array(
        date("Y-m-d", $monday),
        date("Y-m-d", $sunday),
    );
    $relative_time = $monday;
}

var_dump($weeks);

输出：

array
  0 => 
    array
      0 => string '2010-09-20' (length=10)
      1 => string '2010-09-26' (length=10)
  1 => 
    array
      0 => string '2010-09-13' (length=10)
      1 => string '2010-09-19' (length=10)
  2 => 
    array
      0 => string '2010-09-06' (length=10)
      1 => string '2010-09-12' (length=10)
  3 => 
    array
      0 => string '2010-08-30' (length=10)
      1 => string '2010-09-05' (length=10)
  4 => 
    array
      0 => string '2010-08-23' (length=10)
      1 => string '2010-08-29' (length=10)
  5 => 
    array
      0 => string '2010-08-16' (length=10)
      1 => string '2010-08-22' (length=10)
  6 => 
    array
      0 => string '2010-08-09' (length=10)
      1 => string '2010-08-15' (length=10)

Answer 2

使用strtotime获取星期一，然后减去每周的秒数：

function lastnweeks($n) {
    $time = strtotime('Monday 00:00:00+0000');
    $arr = array();
    while ($n-- > 0) {
        $arr[] = array_reverse(array(
            date('Y/m/d', $time-=86400),   // sunday
            date('Y/m/d', $time-=6*86400)  // monday
        ));
    }
    return $arr;
}

array_reverse用于在计算倒退时反转数组。

Answer 3

选择

$last_week = strtotime('last Week');
echo "Last Week ".date("Y/m/d", $last_week)."<br />\n";

或

$last_week = mktime(0,0,0,date("m"),date("d")-7,date("Y"));
echo "Last Week ".date("Y/m/d", $last_week)."<br />\n";

php函数获取最近7周的日期

3 个答案: