Question

我想知道是否有办法在SQL中获取最后两周及其金额，我解释一下：

以下查询以这种方式告诉我过去两周的产品数量：

SELECT pr_products.product,
       WEEKOFYEAR(pf_harvest.date) AS week, 
       SUM(pf_harvest.quantity) AS quantity
       FROM pf_harvest
       INNER JOIN pr_products ON pr_products.id = pf_harvest.id_product
       WHERE pf_harvest.date BETWEEN '2016-08-15' AND '2016-08-28'
       AND pf_harvest.id_tenant = 1
       AND pf_harvest.id_product = 1
       GROUP BY product, WEEKOFYEAR(pf_harvest.date);

我得到的结果如下：

-------------------------------------
product     |    week  |   quantity |
-------------------------------------
ROSA PINK   |    33    |    1076000 |
-------------------------------------
ROSA PINK   |    34    |    1094025 |
-------------------------------------

没关系，问题是我希望查询结果给我留下这样的东西：

-------------------------------------
product     |    week1 |   week2    |
-------------------------------------
ROSA PINK   |  1076000 |    1094025 |
-------------------------------------

这是为了获得在第33周和第34周分组的单个产品的数量，我不知道是否可以这样做，谢谢！

Answer 1

你应该使用条件aggergation。每列仅聚合其周。因此，一次通过一个查询将获得两个聚合。

describe('myDirective', function () {
    'use strict';

    var element,
        dirCtrlScp,
        $compile,
        $rootScope,
        $scope;

    beforeEach(module('myApp'));

    beforeEach(inject(function (_$compile_, _$rootScope_) {
        $compile = _$compile_;
        $rootScope = _$rootScope_;
        $scope = $rootScope.$new();

        element = compileElement();
    }));

    function compileElement() {
        var element = angular.element('<my-directive></my-directive>');
        var compiledElement = $compile(element)($scope);
        dirCtrlScp = element.controller;
        $scope.$digest();

        return compiledElement;
    }

    it('should execute f', function () {
        dirCtrlScp.f();
        expect(dirCtrlScp.value).toBe(true); // there we can access to isolate scope from directive;
    });
});

Answer 2

实现类似Union Select的使用

    SELECT pr_products.product,

       SUM(pf_harvest.quantity) AS week1
       FROM pf_harvest
       INNER JOIN pr_products ON pr_products.id = pf_harvest.id_product
       WHERE pf_harvest.date BETWEEN '2016-08-15' AND '2016-08-21'
       AND pf_harvest.id_tenant = 1
       AND pf_harvest.id_product = 1
       GROUP BY product, WEEKOFYEAR(pf_harvest.date);
UNION
    SELECT 
       SUM(pf_harvest.quantity) AS week2
       FROM pf_harvest
       INNER JOIN pr_products ON pr_products.id = pf_harvest.id_product
       WHERE pf_harvest.date BETWEEN '2016-08-21' AND '2016-08-28'
       AND pf_harvest.id_tenant = 1
       AND pf_harvest.id_product = 1
       GROUP BY product, WEEKOFYEAR(pf_harvest.date);

第一个选择获取第1周的数据，第二个获取第2周的数据。

有关联盟的更多信息，请参阅mysql

Answer 3

我确信这不是最好的方法，但你可以使用偏移合并来引入它。如果内存服务，这应该将字段标记为product | week | week（1）| week（2）| .. ..

Answer 4

你有没有尝试过这样的事情：

SELECT pr_products.product,
       SUM(h1.quantity) AS Week1,
       SUM(h2.quantity) AS Week2
       FROM pr_product
       LEFT JOIN pf_harvest h1 ON pr_products.id = h1.id_product ,
       LEFT JOIN pf_harvest h2 ON pr_products.id = h2.id_product
       WHERE 
       ( h1.date BETWEEN '2016-08-15' AND '2016-08-21'
       AND h1.id_tenant = 1
       AND h1.id_product = 1 )  
    OR
       ( h2.date BETWEEN '2016-08-22' AND '2016-08-28'
       AND h2.id_tenant = 1
       AND h2.id_product = 1 )  
       GROUP BY product ;

获取最近两周的SQL

4 个答案: