Question

我想知道如何从data.table中的值中减去等级。我的MWE如下所示。

set.seed(12345)
A <- rep(x=paste0("A", 1:2), each=6)
B <- rep(x=paste0("B", 1:3), each=2, times=2)
Rep <- rep(x=1:2, times=3)
Y <- rnorm(n=12, mean = 50, sd = 5)

library(data.table)
dt <- data.table(A, B, Rep, Y)

dt[, j=mean(Y), by=.(A, B)]
dt[, j=mean(Y), by=.(A)]

dt[, j=mean(Y), by=.(A, B)] - dt[, j=mean(Y), by=.(A)]

Error in Ops.data.frame(dt[, j = mean(Y), by = .(A, B)], dt[, j = mean(Y),  : 
  ‘-’ only defined for equally-sized data frames

被修改

我想要这个：

dt[, j=mean(Y), by=.(A, B)] - dt[, j=mean(Y), by=.(A)] - dt[, j=mean(Y), by=.(B)] + dt[, j=mean(Y)]

Answer 1

你得到错误的原因是你减去的两个data.table的维度是不同的。另一方面，您可以使用data.table：

进行链式转换

dt[, j := mean(Y), .(A, B)][, j := j - mean(Y), .(A)]
dt
     A  B Rep        Y          j
 1: A1 B1   1 52.92764  3.6373822
 2: A1 B1   2 53.54733  3.6373822
 3: A1 B2   1 49.45348 -1.0071061
 4: A1 B2   2 47.73251 -1.0071061
 5: A1 B3   1 53.02944 -2.6302761
 6: A1 B3   2 40.91022 -2.6302761
 7: A2 B1   1 53.15049  0.1752053
 8: A2 B1   2 48.61908  0.1752053
 9: A2 B2   1 48.57920 -3.7182851
10: A2 B2   2 45.40339 -3.7182851
11: A2 B3   1 49.41876  3.5430798
12: A2 B3   2 59.08656  3.5430798

对于更新，您可以执行以下操作：

dt[, j := mean(Y), .(A, B)][, j := j - mean(Y), .(A)][, j := j - mean(Y), .(B)][, j := j + mean(Y)]
dt
     A  B Rep        Y         j
 1: A1 B1   1 52.92764  1.731088
 2: A1 B1   2 53.54733  1.731088
 3: A1 B2   1 49.45348  1.355590
 4: A1 B2   2 47.73251  1.355590
 5: A1 B3   1 53.02944 -3.086678
 6: A1 B3   2 40.91022 -3.086678
 7: A2 B1   1 53.15049 -1.731088
 8: A2 B1   2 48.61908 -1.731088
 9: A2 B2   1 48.57920 -1.355590
10: A2 B2   2 45.40339 -1.355590
11: A2 B3   1 49.41876  3.086678
12: A2 B3   2 59.08656  3.086678

data.table：减去级别意味着从值

1 个答案: