我有一些代码可以生成分层加权平均值 我确信这几个月前就有效了。但是,但我不确定目前的问题是什么。 (我道歉 - 这一定是非常基本的东西):
dp=
structure(list(seqn = c(1L, 2L, 3L, 4L, 6L, 7L, 8L, 9L, 10L,
11L, 12L, 13L, 3L, 4L, 9L, 10L, 11L, 14L, 8L, 11L, 12L, 10L,
5L, 13L, 2L, 14L, 3L, 9L, 6L, 7L), sex = c(2L, 1L, 2L, 2L, 1L,
2L, 2L, 1L, 2L, 2L, 2L, 1L, 1L, 2L, 2L, 1L, 1L, 2L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L), bmi = c(22.8935608711259,
27.0944623781918, 40.4637162938634, 23.7649712675423, 15.3193372705538,
31.1280302540991, 21.4866354393239, 20.3200254374398, 32.331092513536,
25.3679771839413, 33.9400508162971, 14.7048592172926, 25.5243757788688,
23.4331882363495, 27.6428134168995, 29.3923629426172, 24.9547209666314,
17.0522203606383, 15.51, 22, 30.62, 30.94, 29.1, 25.57, 24.9,
27.33, 17.63, 18.48, 22.56, 29.39), tc = c(273L, 181L, 150L,
201L, 142L, 165L, 235L, 219L, 298L, 222L, 143L, 134L, 268L, 160L,
236L, 225L, 260L, 140L, 162L, 132L, 156L, 140L, 279L, 314L, 215L,
174L, 129L, 148L, 153L, 245L), swt = c(1645, 3318, 2280, 1574,
4062, 1627, 14604, 24675, 975, 975, 2697, 1559, 1737.58, 1730.23,
19521.36, 28080.57, 1248.43, 13745.77, 5251.76464426326, 6497.194885522,
15915.7023420765, 3740.96809540218, 16574.177622509, 307.32513798849,
4720.89748295751, 3247.78896499604, 7698.70949077031, 1262.6450411464,
6609.43340735515, 4254.23723479882)), .Names = c("seqn", "sex",
"bmi", "tc", "swt"), row.names = c(20560L, 20561L, 20562L, 20563L,
20565L, 20566L, 20567L, 20568L, 20569L, 20570L, 20571L, 20572L,
61335L, 61336L, 61338L, 61339L, 61340L, 61341L, 95465L, 96890L,
104613L, 105988L, 107581L, 112267L, 113403L, 114292L, 119979L,
120271L, 125939L, 135699L), class = "data.frame")
dt=data.table(dp, key='sex')
sapply(df,function(x)weighted.mean(x,df$swt)) #this works to weighted mean
dt[,lapply(.SD, mean, na.rm=T), .SDcols=c('bmi','tc','swt')]
#this also works for overall unweighted mean
dt[,lapply(.SD, function(x)weighted.mean(x,swt, na.rm=TRUE)), by=key(dt), .SDcols=c('bmi','tc','swt')]
但是这会给出错误:
Error in weighted.mean.default(x, swt, na.rm = TRUE) : object 'swt' not found
sessionInfo()
R version 2.15.2 (2012-10-26)
Platform: i386-w64-mingw32/i386 (32-bit)
locale:
[1] LC_COLLATE=English_United States.1252 LC_CTYPE=English_United States.1252
[3] LC_MONETARY=English_United States.1252 LC_NUMERIC=C
[5] LC_TIME=English_United States.1252
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] data.table_1.8.6
loaded via a namespace (and not attached):
[1] tools_2.15.2
答案 0 :(得分:8)
当优化“开启”时,o
DT[, lapply(.SD, function(), by=]
没有看到DT的列。现在已修复此问题#2381。测试成功添加和测试。感谢David F报告SO: data.table and stratified means
这确实是介于1.8.2和1.8.6之间的错误。
dt[,lapply(.SD, function(x) weighted.mean(x,swt, na.rm=TRUE)), by=key(dt),
.SDcols=c('bmi','tc','swt')]
Error in weighted.mean.default(x, swt, na.rm = TRUE) :
object 'swt' not found
要解决此问题,请关闭优化:
options(datatable.optimize=FALSE)
dt[,lapply(.SD, function(x)weighted.mean(x,swt, na.rm=TRUE)), by=key(dt),
.SDcols=c('bmi','tc','swt')]
sex bmi tc swt
1: 1 25.64376 206.0115 17171.20
2: 2 23.73566 193.8727 11467.47
或者,不要用function()
包裹:
options(datatable.optimize=TRUE)
dt[,lapply(.SD, weighted.mean, swt, na.rm=TRUE), by=key(dt),
.SDcols=c('bmi','tc','swt')]
sex bmi tc swt
1: 1 25.64376 206.0115 17171.20
2: 2 23.73566 193.8727 11467.47
我们现在正在更多地使用优化,但是这个案例在测试套件中滑落:测试825.1,825.2和825.3没有在匿名function()
内覆盖函数作为另一列的参数。如果没有给出功能,那将是一个问题;即,与这种情况不同,function()
可以省略weighted.mean
,因为verbose=TRUE
已经给出,可以按原样应用。
您可以通过设置{{1}}(每个查询或使用全局选项)来查看优化如何修改j。在这种情况下,没有任何东西可以通过冗长的输出显示为错误,而只是将其视为一边。
现在以#2381: Optimization of lapply(.SD, function() ...) no longer sees columns inside ...提交。将修复并添加测试,这样就不会再次退化。
谢谢!
答案 1 :(得分:3)
我建议保持简单:
dt[,list(bmi_m=weighted.mean(bmi,swt,na.rm=TRUE),
tc_m=weighted.mean(tc,swt,na.rm=TRUE),
swt_m=weighted.mean(swt,swt,na.rm=TRUE)),by=key(dt)]
我认为这也相当快。