Question

我的表格如下所示

SalesOrderNo
------------
1
2
D1
D2
D11
D12
D16
D20
D21

我想要搜索并找到比D16更重要的所有销售工程师这就是我试过的

Select SalesOrderNo From tbl_Sales Where SalesOrderNo > 'D16' and  SalesOrderNo LIKE 'D%'

这就是我得到的

D2
D20
D21

The Desierd Out Put是

D20
D21

Answer 1

使用RIGHT函数在右侧部分找到整数。

<强>查询

select SalesOrderNo from tbl_sales
where SalesOrderNo LIKE 'D%'
and cast(right(SalesOrderNo, len(SalesOrderNo) - 1) as int) > 16;

Demo

Answer 2

试试这个。

假设在D之后只有数字。

     Select SalesOrderNo From tbl_Sales 
        Where to_number(replace(SalesOrderNo,'D','')) > 16 
        and  SalesOrderNo LIKE 'D%'

Answer 3

您需要一种方法来表示D和任何其他带有数字的字母。

select * from 
@tbl_Sales 


where 
    order by 
    case
    when SalesOrderNo like 'D%' then cast(replace(SalesOrderNo,'D','') as int) + 100000
    else cast(SalesOrderNo as int) 
    END > 100016--D16

order by 
case
when SalesOrderNo like 'D%' then cast(replace(SalesOrderNo,'D','') as int) + 100000
else cast(SalesOrderNo as int) 
END

虽然如果你有一个大表，我建议你创建另一个列并用这个整数值填充它以达到性能目的。

Answer 4

您可以使用以下查询

DECLARE @InputColumn AS VARCHAR(20)
SET @InputColumn = 'D16'
SELECT  SalesOrder
FROM    dbo.Section
WHERE   CONVERT(INT, SUBSTRING(SalesOrder, PATINDEX('%[0-9]%', SalesOrder),
                               LEN(SalesOrder))) > CONVERT(INT, SUBSTRING(@InputColumn,
                                                              PATINDEX('%[0-9]%',
                                                              @InputColumn),
                                                              LEN(@InputColumn)))
ORDER BY LEFT(SalesOrder, PATINDEX('%[0-9]%', SalesOrder) - 1) ,
        CONVERT(INT, SUBSTRING(SalesOrder, PATINDEX('%[0-9]%', SalesOrder),
                               LEN(SalesOrder)))

如何找到大于字母数字的数字

4 个答案:

Demo