请耐心等待我,因为我是用C ++自学的,并且在工作上花了我有限的额外时间来尝试更多地了解它(我白天是化学工程研究员)。
我有一个非常简单的目标: 1.制作一个尺寸安全的容器来存储一长串浮子。 2.创建一个充当矩阵的容器的专用版本。
到目前为止,根据我在此提出的各种问题的一些反馈,我得出的是:
template<typename T>
class VectorDeque
{
public:
void resize_index(unsigned int index) {
if ( my_container == VECTOR ) {
try {
my_vector.resize(index);
my_container = VECTOR;
}
catch(std::bad_alloc &e) {
my_deque.resize(index);
my_container = DEQUE;
}
}
else if ( my_container == DEQUE ) {
my_deque.resize(index);
}
}
T operator[](unsigned int index) {
T ret_val;
if ( STORAGE_CONTAINER == VECTOR ) {
ret_val = my_vector[index];
}
else if ( STORAGE_CONTAINER == DEQUE ) {
ret_val = my_deque[index];
}
}
private:
enum STORAGE_CONTAINER { NONE, DEQUE, VECTOR };
std::vector<T> my_vector;
std::deque<T> my_deque;
STORAGE_CONTAINER my_container;
T& get(int index) {
T temp_val;
if(my_container == VECTOR) {
temp_val = my_vector[index];
}
else if(my_container == DEQUE) {
temp_val = my_deque[index];
}
return temp_val;
}
};
template<typename T>
class VectorDeque2D: public VectorDeque<T>
{
public:
template<typename T>
class VectorDeque2D_Inner_Set
{
VectorDeque2D& parent;
int first_index;
public:
// Just init the temp object
VectorDeque2D_Inner_Set(My2D& p, int first_Index) :
parent(p),
first_Index(first_index) {}
// Here we get the value.
T& operator[](int second_index) const
{ return parent.get(first_index,second_index);}
};
// Return an object that defines its own operator[] that will access the data.
// The temp object is very trivial and just allows access to the data via
// operator[]
VectorDeque2D_Inner_Set<T> operator[](unsigned int first_index) {
return VectorDeque2D_Inner_Set<T>(*this, first_index);
}
void resize_index_second(unsigned int second_index) {
if ( my_container == VECTOR ) {
try {
for (unsigned int couter=0;couter < my_vector.size(); counter++) {
my_vector[counter].resize(second_index);
}
my_container = VECTOR;
}
catch(std::bad_alloc &e) {
for (unsigned int couter=0;couter < my_deque.size(); counter++) {
my_deque[counter].resize(second_index);
}
my_container = DEQUE;
}
}
else if ( my_container == DEQUE ) {
for (unsigned int couter=0;couter < my_deque.size(); counter++) {
my_deque[counter].resize(second_index);
}
}
}
void resize(unsigned int first_index,
unsigned int second_index) {
if ( my_container == VECTOR ) {
try {
my_vector.resize(first_index);
for (unsigned int couter=0;couter < my_vector.size(); counter++) {
my_vector[counter].resize(second_index);
}
my_container = VECTOR;
}
catch(std::bad_alloc &e) {
my_deque.resize(first_index);
for (unsigned int couter=0;couter < my_deque.size(); counter++) {
my_deque[counter].resize(second_index);
}
my_container = DEQUE;
}
}
else if ( my_container == DEQUE ) {
my_deque.resize(first_index);
for (unsigned int couter=0;couter < my_deque.size(); counter++) {
my_deque[counter].resize(second_index);
}
}
}
private:
enum STORAGE_CONTAINER { NONE, DEQUE, VECTOR };
friend class VectorDeque2D_Inner_Set;
std::vector<std::vector<T> > my_vector;
std::deque<std::deque<T> > my_deque;
STORAGE_CONTAINER my_container;
T& get(int first_index,int second_index) {
T temp_val;
if(my_container == VECTOR) {
temp_val = my_vector[first_index][second_index];
}
else if(my_container == DEQUE) {
temp_val = my_deque[first_index][second_index];
}
return temp_val;
}
};
通过这个实现,我试图:
1。向包装的用户提供两个访问选项(“.get(x,y)”和“[x] [y]”))
2。通过使用基于包装的类然后继承它以生成矩阵来最大化重用。
3. 如果达到连续内存限制,解决从向量转换为双端队列的问题。
这看起来像是一个不错的解决方案吗?建议?
答案 0 :(得分:2)
你看过Boost::Matrix了吗?在该库中已经构建了许多数字和线性代数。
编辑:
在阅读有关在达到大小限制时从向量转换为双端队列的评论后,请使用deque
。像这样“花哨”会降低你的生产力。专注于手头的问题,让收藏担心记忆。 Deque对于大型数组来说非常快,并且与向量相比只释放内存时会受到影响。
答案 1 :(得分:0)
对我来说,在单次使用过程中两者之间的转换似乎不值得付出努力。
如果要通过自己的方式执行此操作,可以定义第二个模板参数,该参数允许在编译时指定容器类型。然后,您不需要vector
和deque
作为成员,类型转换代码就会消失。
template<typename T, typename CONTAINER>
class VectorDeque
{
// snip
private:
CONTAINER<T> _storage;
};