Question

我不确定最好的办法。我想迭代我的json并找到所有在美国的公司。这个JSON可能会随着我的应用程序的增长而变得更加复杂，就像在关卡，对象等中一样。我只是想知道人们使用JSON和{过滤掉数据子集的简单搜索方式{1}}和/或Node.js或库可能是ES6等等。

所以，例如这个json，有什么方法可以搜索它并且只撤回那些在美国的公司？

Lodash

Answer 1

对Array#filter

使用JavaScript原生 ES6 arrow function 方法

var res = data.filter(v => v.location.country === 'USA');

＆＃13;

var data = [{
  "id": 0,
  "name": "Company1",
  "logoUrl": "/lib/assets/company1-logo.png",
  "location": {
    "country": "USA",
    "state": "California",
    "city": "Napa"
  },
  "active": false
}, {
  "id": 1,
  "name": "Company2",
  "logoUrl": "/lib/assets/company2-logo.png",
  "location": {
    "country": "Germany",
    "state": "",
    "city": "Berlin"
  },
  "active": false
}, {
  "id": 2,
  "name": "Company3",
  "logoUrl": "/lib/assets/company3-logo.png",
  "location": {
    "country": "USA",
    "state": "Michigan",
    "city": "Detroit"
  },
  "active": false
}];

var res = data.filter(v => v.location.country === 'USA');

console.log(res);

＆＃13;

Answer 2

您可以使用JavaScript的简单.filter()方法返回完成过滤器的结果列表。假设您的数据在可变数据中

<强> ES5

data.filter(function(item) {
  return item.location.country === 'USA';
});

ES6 ：在ES6中，您可以使用与

相同的箭头功能

data.filter((item) => {
  return item.location.country === 'USA';
});

＆＃13;

var data = [{
    "id": 0,
    "name": "Company1",
    "logoUrl": "/lib/assets/company1-logo.png",
    "location":{
      "country": "USA",
      "state": "California",
      "city": "Napa"
    },
    "active": false
  },
  {
    "id": 1,
    "name": "Company2",
    "logoUrl": "/lib/assets/company2-logo.png",
    "location":{
      "country": "Germany",
      "state": "",
      "city": "Berlin"
    },
    "active": false
  },
  {
    "id": 2,
    "name": "Company3",
    "logoUrl": "/lib/assets/company3-logo.png",
    "location":{
      "country": "USA",
      "state": "Michigan",
      "city": "Detroit"
    },
    "active": false
  }];

var res1 = data.filter(function(item) {
  return item.location.country === 'USA';
});

const res2 = data.filter((item) => {
  return item.location.country === 'USA';
});

console.log(res1);
console.log(res2);

＆＃13;

Answer 3

在lodash中它将是

_.filter(data, function(item) {
  return item.location.country === 'USA';
});

Answer 4

您可以使用原生过滤功能。

const items = [{
    "id": 0,
    "name": "Company1",
    "logoUrl": "/lib/assets/company1-logo.png",
    "location":{
      "country": "USA",
      "state": "California",
      "city": "Napa"
    },
    "active": false
  },
  {
    "id": 1,
    "name": "Company2",
    "logoUrl": "/lib/assets/company2-logo.png",
    "location":{
      "country": "Germany",
      "state": "",
      "city": "Berlin"
    },
    "active": false
  },
  {
    "id": 2,
    "name": "Company3",
    "logoUrl": "/lib/assets/company3-logo.png",
    "location":{
      "country": "USA",
      "state": "Michigan",
      "city": "Detroit"
    },
    "active": false
  }]

const usItems = items.filter(v => v.location.country === 'USA')

使用Node或ES6从JSON过滤记录

4 个答案: