Question

我正在一个可以搜索音乐的网站上工作。我想在一个过滤器选项中，人们可以过滤最小年龄。

这是我的JSON文件：

{
  "artists":[
{
"name": "Martin Garrix",
"origin": "Netherlands",
"age": "22 years old",
"artist_id": "c0dc129d8a886a2c9bf487b826c3614a6630fb9c",
"best_song":"https://w.soundcloud.com/player/?url=https%3A//api.soundcloud.com/tracks/98081145&color=%23ff5500&auto_play=false&hide_related=false&show_comments=true&show_user=true&show_reposts=false&show_teaser=true"

},

{
  "name": "Armin van Buuren",
  "origin": "Netherlands",
  "age": "41 years old",
  "artist_id": "8b0a178ce06055312456cccc0c9aa7679d8054f1",
  "best_song":"https://w.soundcloud.com/player/?url=https%3A//api.soundcloud.com/tracks/181749728&color=%23ff5500&auto_play=false&hide_related=false&show_comments=true&show_user=true&show_reposts=false&show_teaser=true"
},

{
  "name": "Don Diablo",
  "origin": "Netherlands",
  "age": "38 years old",
  "artist_id": "178c6e7e3bf24710d4895048586a86f1bb81d842",
  "best_song":"https://w.soundcloud.com/player/?url=https%3A//api.soundcloud.com/tracks/212802517&color=%23ff5500&auto_play=false&hide_related=false&show_comments=true&show_user=true&show_reposts=false&show_teaser=true"


},

{
  "name": "David Guetta",
  "origin": "France",
  "age": "50 years old",
  "artist_id": "c2714423228a8012ad37af0186447cbb7ff589f7",
  "best_song":"https://w.soundcloud.com/player/?url=https%3A//api.soundcloud.com/tracks/140006470&color=%23ff5500&auto_play=false&hide_related=false&show_comments=true&show_user=true&show_reposts=false&show_teaser=true"


},

{
  "name": "Alesso",
  "origin": "Sweden",
  "age": "26 years old",
  "artist_id": "69fa09f6e181093fe0ea2ce1a4099066509f7837",
  "best_song":"https://w.soundcloud.com/player/?url=https%3A//api.soundcloud.com/tracks/288914798&color=%23ff5500&auto_play=false&hide_related=false&show_comments=true&show_user=true&show_reposts=false&show_teaser=true"

}
]
}

这是我的HTML：

<div class = "div-age">
<label for="age-select">Minimum age</label>
<input type="text" class = "search-age">
</div>

所以例如;如果你在输入字段中输入40，那么你只能得到＃Armin van Buuren＆＃34;和＃34; David Guetta＆＃34;。

这就是我现在所拥有的。

document.querySelector(`.search-age`).addEventListener(`keyup` , e => {
    const term = e.target.value.toLowerCase();
    const ageList = document.getElementsByClassName(`artist-info`);
    Array.from(ageList).forEach(function(ageList) {
      const artistAge = ageList.querySelector(`.age`).textContent;
      if (artistAge.toLowerCase().includes(term)) {
        ageList.style.display = `flex`;
      } else {
        ageList.style.display = `none`;
      }
    })
  });

我现在遇到的问题是它只过滤确切的数字。例如，我把22，我只得到＆＃34; Martin Garrix＆＃34;

Answer 1

使用filter()，您可以执行以下操作：

＆＃13;

blockSignals()

＆＃13;

Answer 2

您可以尝试使用parseInt将年龄字符串转换为相应的数字，然后将其与值进行比较：

// Convert term and artist's age to corresponding integers
term = parseInt(term, 10);
artistAge = parseInt(artistAge, 10);

if (artistAge >= term) {
  ageList.style.display = `flex`;
} else {
  // ...
}

Answer 3

有几件事：

你不需要Template literals，你可以使用普通字符串。
不要使用keyup，而是使用input作为此类事件的事件：如果用户使用与键盘不同的设备粘贴值，它也可以获取内容 - 例如鼠标。
不要使用getElementsByClassName，因为它会返回实时HTMLCollection。请改用querySelectorAll，返回静态NodeList。它还直接支持forEach，因此您无需使用Array.from。
不要shadowing变量，例如您编写的代码中的ageList：它可能会导致意外错误。

说：

// you might not want to query all the time this list,
// every time the user change the input value.
const ageList = document.querySelectorAll('.artist-info');

document.querySelector('.search-age').addEventListener('input' , e => {
    // no need to lowercase, it's numeric.
    // you might want to add some check or constraint on
    // <input> validation
    const term = +e.target.value;

    ageList.forEach(node => {
      const artistAge = node.querySelector('.age').textContent;
      node.style.display = parseInt(artistAge, 10) >= term ? 'flex' : 'none';
    })
  });

（ES6）使用输入字段过滤数据（min.array）

3 个答案: