Question

我想通过将DB值放入下拉列表来选择选项，以下是我使用过的代码，

$query = "SELECT apply_year FROM emp_leaves ORDER BY apply_year DESC";
$result = mysql_query($query);
echo "<select name='apply_year' class=\"form-control\"><option>Select Year</option>";
while ($r = mysql_fetch_array($result)) {
    echo "<option value=" . $r['leave_id'] . ">" . $r['apply_year'] . "</option>";
}
echo "</select>"; ?>

它工作正常，但我想每年只显示一个值，我想避免在同一年下降。请帮忙

Answer 1

对apply_year和Create mysql查询使用DISTINCT，这样它只会在结果中返回apply_year一次：

$query = "SELECT DISTINCT apply_year FROM emp_leaves ORDER BY apply_year DESC";

Answer 2

试试这个，

$query = "SELECT apply_year FROM emp_leaves GROUP BY apply_year  ORDER BY apply_year DESC";
$result = mysql_query($query);
echo "<select name='apply_year' class=\"form-control\"><option>Select Year</option>";
while ($r = mysql_fetch_array($result)) {
     echo "<option value=" . $r['leave_id'] . ">" . $r['apply_year'] . "</option>";
}
echo "</select>"; ?>

将数据库数据拉入MYSQL中的下拉列表，PHP

2 个答案: