Question

我有五个NSMutableArray每个NSMutableArray持有另一个对象数组...我想将所有五个NSMutableArray存储在一个数组中...我该怎么做？

    NSMutableArray *mA1 = [NSMutableArray array];
    NSMutableArray *mA2 = [NSMutableArray array];
    NSMutableArray *mA3 = [NSMutableArray array];
    NSMutableArray *mA4 = [NSMutableArray array];
    NSMutableArray *mA5 = [NSMutableArray array];

并将所有五个NSMutableArray存储在一个数组中..如何从该数组中检索NSMutableArray ....

Answer 1

在for周期中执行此操作，无需使用5个实例编写重复代码：

NSMurableArray *container = [NSMutableArray new];
for (int index = 0; index < 5; index++) {
     [container addObject:[NSMutableArray new]];
}

然后通过container[2]

访问它们

Answer 2

NSMutableArray *mA1 = [NSMutableArray array];
NSMutableArray *mA2 = [NSMutableArray array];
NSMutableArray *mA3 = [NSMutableArray array];
NSMutableArray *mA4 = [NSMutableArray array];
NSMutableArray *mA5 = [NSMutableArray array];


NSArray *combinedArray = [NSArray arrayWithObjects:mA1,mA2,mA3,mA4,mA5,nil];

or
NSArray *combinedArray = @[mA1,mA2,mA3,mA4,mA5]; //immutable
NSMutableArray *combinedArray = [@[mA1,mA2,mA3,mA4,mA5]mutableCopy]; // mutable

Answer 3

你可以这样做。首先将所有5个数组添加到NSMutableArray中，例如“mainArray”，如下所示

NSMutableArray *mainArray = [[NSMutablearray alloc]initWithObjects:mA1,mA2,mA3,mA4,mA5,nil];

这会将所有5个数组添加到主数组中。现在要从数组中检索它们，你可以这样做

NSMutablearray *array = [mainArray objectAtIndex:0];//here pass index of array you want to get

或者您使用for循环来迭代mainArray中的所有数组。希望这会对你有所帮助

Answer 4

NSMutableArray *mA1 = [NSMutableArray array];
NSMutableArray *mA2 = [NSMutableArray array];
NSMutableArray *mA3 = [NSMutableArray array];
NSMutableArray *mA4 = [NSMutableArray array];
NSMutableArray *mA5 = [NSMutableArray array];

NSArray *yourArray = @[mA1, mA2, mA3, mA4, mA5];//yourArray store all five NSMutableArray

for (int i = 0; i < yourArray.count; i++) {
    NSMutableArray *mA = array[i];//mA is the NSMutableArray(mA1 or other).
}

我可以在一个数组中存储多个NSMutableArray？

4 个答案: