无法将数据从旧表迁移到新表

时间：2016-06-10 13:36:59

标签： sql sql-server tsql

我有两个表要用新表替换。旧表：

CREATE TABLE [dbo].[OldContacts](
    [OldContactID] [int] IDENTITY(1,1) NOT NULL,
    [ClientID] [int] NULL,
    [BusinessID] [int] NULL,
    [Title] [varchar](20) NULL,
    [FirstName] [varchar](100) NULL,
    [Surname] [varchar](100) NULL,
    [JobTitle] [varchar](100) NULL,
    [EmailAddress] [varchar](100) NULL,
    [Telephone] [varchar](20) NULL,
    [Mobile] [varchar](20) NULL,
    [DecisionMaker] [int] NULL,
    [PrimaryContact] [int] NULL,
    [ContactDisabled] [int] NULL,
    [ZoomInfoPersonId] [int] NULL,
    [CreationDate] [datetime] NULL,
    [BusinessListRecordID] [int] NULL)

CREATE TABLE [dbo].[Transaction](
    [TransactionId] [int] IDENTITY(1,1) NOT NULL,
    [CreditTransactionId] [int] NOT NULL,
    [PersonId] [int] NOT NULL,
    [CompanyId] [int] NOT NULL,
    [CompanyName] [nvarchar](150) NOT NULL,
    [ContactName] [nvarchar](150) NOT NULL,
    [ContactEmail] [nvarchar](150) NULL,
    [ContactPhone] [nvarchar](50) NULL,
    [ContactJobTitle] [nvarchar](150) NULL,
    [EmailBought] [bit] NULL,
    [AddressLine1] [varchar](100) NULL,
    [AddressLine2] [varchar](100) NULL,
    [AddressLine3] [varchar](100) NULL,
    [County] [varchar](100) NULL,
    [Town] [varchar](100) NULL,
    [Country] [varchar](100) NULL,
    [Telephone] [varchar](100) NULL,
    [Website] [varchar](500) NULL,
    [Industry] [varchar](100) NULL,
    [BusinessID] [int] NULL)

新的：

CREATE TABLE [dbo].[ClientContacts](
    [ClientContactID] [int] IDENTITY(1,1) NOT NULL,
    [ClientUserID] [int] NULL,
    [PersonID] [int] NULL,
    [BusinessID] [int] NULL,
    [CompanyID] [int] NULL,
    [CompanyName] [varchar](50) NULL,
    [ContactName] [varchar](100) NULL,
    [ContactFirstName] [varchar](50) NULL,
    [ContactSurname] [varchar](50) NULL,
    [ContactEmail] [varchar](50) NULL,
    [ContactPhone] [varchar](50) NULL,
    [ContactMobile] [varchar](50) NULL,
    [ContactJobTitle] [varchar](50) NULL,
    [EmailBought] [bit] NULL,
    [AddressLine1] [varchar](50) NULL,
    [AddressLine2] [varchar](50) NULL,
    [AddressLine3] [varchar](50) NULL,
    [County] [varchar](50) NULL,
    [Town] [varchar](50) NULL,
    [Country] [varchar](50) NULL,
    [CompanyTelephone] [varchar](50) NULL,
    [CompanyWebsite] [varchar](50) NULL,
    [Industry] [varchar](50) NULL,
    [DecisionMaker] [bit] NULL,
    [PrimaryContact] [bit] NULL,
    [ContactDisabled] [bit] NULL,
    [CreationDate] [datetime] NULL,
    [BusinessListRecordID] [int] NULL,
    [IsPurchased] [bit] NULL
)

旧的逻辑是，你在Transaction创建了一条记录，然后它会向OldContacts添加一条记录，创建我们现在试图摆脱的冗余。 但是，您OldContacts上的记录可能不是来自Transaction。

现在，我需要将数据迁移到新表格，获取所有Transaction条记录以及OldContacts不与Transaction重复的INSERT INTO dbo.ClientContacts ( ClientUserID, PersonID, BusinessID, CompanyID, CompanyName, ContactName, ContactFirstName, ContactSurname, ContactEmail, ContactPhone, ContactMobile, ContactJobTitle, EmailBought, AddressLine1, AddressLine2, AddressLine3, County, Town, Country, CompanyTelephone, CompanyWebsite, Industry, DecisionMaker, PrimaryContact, ContactDisabled, CreationDate, BusinessListRecordID, IsPurchased ) SELECT CT.ClientUserId, LC.ZIPersonId, LC.BusinessID, T.CompanyId, T.CompanyName, CONCAT(LC.FirstName, ' ', LC.Surname), LC.FirstName, LC.Surname, LC.EmailAddress, LC.Telephone AS ContactPhone, LC.Mobile AS ContactMobile, LC.JobTitle, T.EmailBought, T.AddressLine1, T.AddressLine2, T.AddressLine3, T.County, T.Town, T.Country, T.Telephone, T.Website, T.Industry, LC.DecisionMaker, LC.PrimaryContact, LC.ContactDisabled, LC.CreationDate, LC.BusinessListRecordID, CASE LC.ZIPersonId WHEN 0 THEN 0 ELSE 1 END FROM OldContacts LC LEFT OUTER JOIN dbo.[Transaction] T ON LC.ZIPersonId = T.PersonId LEFT OUTER JOIN dbo.CreditTransaction CT ON T.CreditTransactionId = CT.CreditTransactionId 条记录。这是我到目前为止所得到的：

INSERT INTO dbo.OldContacts (ClientID, BusinessID, Title, FirstName, Surname, JobTitle, EmailAddress, Telephone, Mobile, DecisionMaker, PrimaryContact, ContactDisabled, ZIPPersonId, CreationDate, BusinessListRecordID)
VALUES
(13832, 10, 'Mr', 'John55', 'Smith55', 'Admin', 'john55@smith.com', '123456', '123456', 0, 0, 0, 55, GETDATE(), NULL)

INSERT INTO dbo.OldContacts (ClientID, BusinessID, Title, FirstName, Surname, JobTitle, EmailAddress, Telephone, Mobile, DecisionMaker, PrimaryContact, ContactDisabled, ZIPPersonId, CreationDate, BusinessListRecordID)
VALUES
(13832, 10, 'Mr', 'John66', 'Smith66', 'Admin', 'john66@smith.com', '123456', '123456', 0, 0, 0, 66, GETDATE(), NULL)

INSERT INTO dbo.OldContacts (ClientID, BusinessID, Title, FirstName, Surname, JobTitle, EmailAddress, Telephone, Mobile, DecisionMaker, PrimaryContact, ContactDisabled, ZIPPersonId, CreationDate, BusinessListRecordID)
VALUES
(13832, 10, 'Mr', 'John77', 'Smith77', 'Admin', 'john77@smith.com', '123456', '123456', 0, 0, 0, 77, GETDATE(), NULL)

-- ******************************************************************************

INSERT INTO dbo.[Transaction] (CreditTransactionId, PersonId, CompanyId, CompanyName, ContactName, ContactEmail, ContactJobTitle, EmailBought, AddressLine1, AddressLine2, AddressLine3, County, Town, Country, Telephone, Website, Industry, BusinessID)
VALUES
(7965, 77, 123, 'TestCompany', 'John77 Smith77', 'john77@smith77.com', 'Admin', 1, 'AL1','AL2', 'AL3', 'testcounty', 'testtown', 'testcountry', '321456', 'www.test.com', 'someIndustry', 10)

但是，这只能得到一条记录，其中ZIPersonId匹配。如何从两个表中获取记录而不会出现重复项？

以下是一些测试记录：

OldContacts

修改

我用LEFT OUTER JOINS替换了两个连接，现在我已经拥有了所有记录。但是，我没有得到一些列：没有来自import java.io.File; import SimpleOpenNI.*; import java.util.*; SimpleOpenNI kinect; void setup() { size(640, 480); kinect = new SimpleOpenNI(this); kinect.enableDepth(); } int precedente = millis(); void draw() { kinect.update(); PImage depthImage = kinect.depthImage(); image(depthImage, 0, 0); int[] depthValues = kinect.depthMap(); StringBuilder sb = new StringBuilder(); Deque<Integer> row = new LinkedList<Integer>(); int kinectheight = 770; // kinect distance from the baselevel [mm] int scaleFactor = 1; int pixelsPerRow = 640; int pixelsToSkip = 40; int rowNum = 0; for (int i = 0; i < depthValues.length; i++) { if (i > 0 && i == (rowNum + 1) * pixelsPerRow) { fillStringBuilder(sb, row); rowNum++; sb.append("\n"); row = new LinkedList<Integer>(); } if (i >= (rowNum * pixelsPerRow) + pixelsToSkip) { row.addFirst((kinectheight - depthValues[i]) * scaleFactor); } } fillStringBuilder(sb, row); String kinectDEM = sb.toString(); final String[] txt= new String[1]; //creates a string array of 2 elements int savingtimestep = 15000; // time step in millisec between each saving if (millis() > precedente + savingtimestep) { txt[0] = "ncols 600\nnrows 480\nxllcorner 0\nyllcorner 0\ncellsize 91.6667\nNODATA_value 10\n" +kinectDEM; saveStrings("kinectDEM0.tmp", txt); precedente = millis(); // delete the old .txt file, from kinectDEM1 to kinectDEMtrash File f = new File (sketchPath("kinectDEM1.txt")); boolean success = f.delete(); // rename the old .txt file, from kinectDEM0 to kinectDEM1 File oldName1 = new File(sketchPath("kinectDEM0.txt")); File newName1 = new File(sketchPath("kinectDEM1.txt")); oldName1.renameTo(newName1); // rename kinectDEM0.tmp file to kinectDEM0.txt File oldName2 = new File(sketchPath("kinectDEM0.tmp")); File newName2 = new File(sketchPath("kinectDEM0.txt")); oldName2.renameTo(newName2); } } void fillStringBuilder(StringBuilder sb, Deque<Integer> row) { boolean emptyRow = false; while (!emptyRow) { Integer val = row.pollFirst(); if (val == null) { emptyRow = true; } else { sb.append(val); val = row.peekFirst(); if (val != null) { sb.append(" "); } } } } 表的联系人的ClientUserId，CompanyId，CompanyName和isPurchased字段总是一个，当它不应该时，如果ZIPersonId不是，则它应该是1 0

2 个答案:

答案 0 :(得分：1)

似乎你必须用LEFT JOIN替换INNER JOIN：

INSERT INTO dbo.ClientContacts
    (
        ClientUserID, PersonID, BusinessID, CompanyID, CompanyName, ContactName,
        ContactFirstName, ContactSurname, ContactEmail, ContactPhone, ContactMobile,
        ContactJobTitle, EmailBought, AddressLine1, AddressLine2, AddressLine3,
        County, Town, Country, CompanyTelephone, CompanyWebsite, Industry,
        DecisionMaker, PrimaryContact, ContactDisabled, CreationDate,
        BusinessListRecordID, IsPurchased
    )
    SELECT
        CT.ClientUserId,
        LC.ZIPersonId,
        LC.BusinessID,
        T.CompanyId,
        T.CompanyName,
        CONCAT(LC.FirstName, ' ', LC.Surname),
        LC.FirstName,
        LC.Surname,
        LC.EmailAddress,
        LC.Telephone AS ContactPhone,
        LC.Mobile AS ContactMobile,
        LC.JobTitle,
        T.EmailBought,
        T.AddressLine1,     
        T.AddressLine2,
        T.AddressLine3,
        T.County,
        T.Town,
        T.Country,
        T.Telephone,
        T.Website,
        T.Industry,
        LC.DecisionMaker,
        LC.PrimaryContact,
        LC.ContactDisabled,
        LC.CreationDate,
        LC.BusinessListRecordID,
        CASE LC.ZIPersonId WHEN 0 THEN 0 ELSE 1 END
    FROM OldContacts LC
    LEFT JOIN dbo.[Transaction] T ON LC.ZIPersonId = T.PersonId
    LEFT JOIN dbo.CreditTransaction CT ON T.CreditTransactionId = CT.CreditTransactionId

即使没有Transactions或CreditTransaction，也会选择OldContacts。

回答你的新问题：

CASE LC.ZIPersonId WHEN 0 THEN 0 ELSE 1 END

应该是

CASE T.PersonId WHEN 0 THEN 0 ELSE 1 END

答案 1 :(得分：0)

首先尝试联合，然后在UNION of

中取消选择所有重复项 
 OLDCONTACTS

和

TRANSACTION.

很难复制你的案子，我会尝试这样的事情：

select the-cols-you-need from
   (
    select a.the-cols-you-need, a.distinct(foreign-key) from
        (
        select * from oldcontacts
        union all
        select * from transaction
        ) as a
   )
inner join CreditTransaction CT on a.transactionId = CT.transactionId
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