Question

我的挑战在以下示例中解释：给出了关键字组合“游戏笔记本”。

我想检查两个关键字是否出现在字符串中。挑战是字符串看起来像这样：

“漂亮的游戏笔记本” “游戏笔记本” “极端游戏笔记本”

我希望我的函数对所有三个字符串都返回true。单词组合之间可以容忍3-4个单词，如示例所示，如果切换关键字，我希望它能够正常工作。

所以我的方法如下，但它似乎不起作用：

$keyword = strtolower("gaming notebook");
$parts = explode(" ", $keyword);

$string = strtolower("Which notebook for good gaming performance");
//point to end of the array
end($parts);
//fetch key of the last element of the array.
$lastElementKey = key($parts);
//iterate the array
$searchExpression = "";
foreach($parts as $k => $v) {
    if($k != $lastElementKey) {
        $searchExpression .= $v . "|";
    } else {
        $searchExpression .= $v;
    }
}

if(preg_match_all('#\b('. $searchExpression .')\b#', $string, $matches) > 0) {
    echo "Jep, keyword combination is in string";
} else {
    echo "No, keyword combination is not in string";
}

Answer 1

您希望在数据库中使用类似CMU Sphinx或自然语言索引的内容。（参见http://dev.mysql.com/doc/refman/5.7/en/fulltext-natural-language.html）快速搜索php库“nlp-tools / nlp-tools”，但是，我从未使用纯php解决方案来完成你想要做的事情。

Answer 2

使用preg_match_all和array_intersect函数的解决方案：

$keywordStr = "gaming notebook";
$string = "Which notebook for good gaming performance,it's my notebook";
$keywords = explode(" ", $keywordStr);
$parts = implode("|", $keywords);

preg_match_all("/\b$parts\b/i", $string, $matches);
// matched items should contain all needed keywords
if (count($keywords) == count(array_intersect($keywords, $matches[0]))) {
    echo "Jep, keyword combination is in string";
} else {
    echo "No, keyword combination is not in string";
}

Answer 3

<?php

$keyword = strtolower("gaming notebook");
$string = strtolower("Which notebooks for good gaming performance");
function check($keyword,$string){
    $parts = explode(' ',$keyword);
    $result = false;
    $pattern = implode('|',$parts);
    preg_match_all("(\b{$pattern}\b)",$string,$matches);
    if(isset($matches[0])){
       return true;
    }

    return false;
}

var_dump(check($keyword, $string));

Answer 4

componentWillMount: function () {
    window.MyVars = {
        ajax: require('../helpers/ajax.jsx'),
        utils: require('../helpers/utils.jsx')
    };
}

当2个关键字出现在字符串中时，按任意顺序并且最多相隔4个字时，这将显示OK。

<强>解释

$reg = "/(?:\b$kw1(?:\s+\w+){0,4}\s+$kw2\b)|(?:\b$kw2(?:\s+\w+){0,4}\s+$kw1\b)/";
if (preg_match($reg, $string)) {
    echo "OK\n";
} else {
    echo "KO\n";
}

PHP检查String中是否出现两个关键字

4 个答案: