Question

我有一个非常大的json有多个字段，我想提取其中的一些，然后将它们写入csv。

这是我的代码：

#!/usr/bin/python3
# -*- coding: utf-8 -*-

import json

import csv

data_file = open("book_data.json", "r")
values = json.load(data_file)
data_file.close()

with open("book_data.csv", "wb") as f:
    wr = csv.writer(f)
    for data in values:
         value = data["identifier"]
         value = data["authors"]
         for key, value in data.iteritems():
               wr.writerow([key, value])

它给了我这个错误：

File "json_to_csv.py", line 22, in <module>
wr.writerow([key, value])
UnicodeEncodeError: 'ascii' codec can't encode character u'\u2019' in position 8: ordinal not in range(128)

但我在顶部给出了utf-8编码，所以我不知道那里有什么错误。

由于

Answer 1

您需要对数据进行编码：

wr.writerow([key.encode("utf-8"), value.encode("utf-8")])

差异相当于：

In [8]: print u'\u2019'.encode("utf-8")
’

In [9]: print str(u'\u2019')
---------------------------------------------------------------------------
UnicodeEncodeError                        Traceback (most recent call last)
<ipython-input-9-4e3ad09ee31b> in <module>()
----> 1 print str(u'\u2019')

UnicodeEncodeError: 'ascii' codec can't encode character u'\u2019' in position 0: ordinal not in range(128)

如果您混合使用字符串，列表和值，则可以使用 issinstance 来检查您拥有的内容，如果您有一个列表迭代并编码：

with open("book_data.csv", "wb") as f:
    wr = csv.writer(f)
    for data in values:
         for key, value in data.iteritems():
               wr.writerow([key, ",".join([v.encode("utf-8") for v in value]) if isinstance(value, list) else value.encode("utf8")])

要只编写三列creator, contributor和identifier，只需使用键提取数据：

import csv

with open("book_data.csv", "wb") as f:
    wr = csv.writer(f)
    for dct in values:
        authors = dct["authors"]
        wr.writerow((",".join(authors["creator"]).encode("utf-8"),
                     "".join(authors["contributor"]).encode("utf-8"),
                     dct["identifier"].encode("utf-8")))

提取json字段并使用python将它们写入csv

1 个答案: