Question

我使用以下查询获取数据

SELECT t1.user_id, t1.time_spent , t1.goal FROM
                (SELECT temp_user_notes.user_id as user_id, temp_user_notes.activity_goal as goal, user_activities.activity_date as dates,
                date(now()) as activity_date, sum(user_activities.time_spent) as time_spent
                FROM temp_user_notes
                INNER JOIN user_activities
                ON temp_user_notes.user_id = user_activities.user_id
                WHERE activity_date = date(now())
                group by user_id, goal, dates,activity_date) as t1
                WHERE time_spent > goal ;

并且它给出了这个结果

 user_id time_spent   goal
    136       3000      0
    135       2000      5

但如果我试图将此结果保存在其他表user_records中，那么它会给我Truncated incorrect datetime value: ''错误。即使我没有插入日期时间字段

insert into user_records
 (user_id,
 goal,
 time_spent)


(SELECT 
t3.user_id, 
t3.goal, 
t3.time_spent
            FROM
            (SELECT t1.user_id, t1.time_spent , t1.goal,t1.activity_date FROM
            (SELECT temp_user_notes.user_id as user_id, temp_user_notes.activity_goal as goal, user_activities.activity_date as dates,
            date(now()) as activity_date, sum(user_activities.time_spent) as time_spent
            FROM temp_user_notes
            INNER JOIN user_activities
            ON temp_user_notes.user_id = user_activities.user_id
            WHERE activity_date = date(now())
            group by user_id, goal, dates,activity_date) as t1
            WHERE time_spent > goal);

愚蠢的是，如果我试图通过user_table插入值，我没有任何日期约束错误。

insert user_records (user_id,goal,time_spent)
            select id , activity_goal as goal, login_count as time_spent
            from users limit 1;

错误截断的日期时间值不正确：＆＃39;＆＃39;在插入查询中

0 个答案: