Question

我正在运行查询并获取mysql错误1292：“截断的INTEGER值不正确” 这是一个警告，我的选择工作正常，但我仍然想清除警告。

我可以确认每次函数找到链接到对象的标记时都会发出警告。如果未找到任何标记，则不会发出警告。因此，如果1000个对象中有50个具有标签，我将收到50个警告，如下所示：

Truncated incorrect INTEGER value: '1|Blondes'

使用的数据库功能是：

DELIMITER $$

DROP FUNCTION IF EXISTS `fnObjectTagGetObjectTags` $$
CREATE DEFINER=`root`@`%` FUNCTION `fnObjectTagGetObjectTags`(_objectType int, _objectId bigint) RETURNS varchar(2048) CHARSET utf8
BEGIN

  DECLARE _outObjectTags VARCHAR(2048);

  SET _outObjectTags =
    (
      SELECT (CAST(GROUP_CONCAT(CONCAT(tagId, '|', tagName) separator '~') AS CHAR(10000) CHARACTER SET utf8)) AS objectTagList
      FROM
      (

      SELECT tagId, tagName
        FROM objectTag
        INNER JOIN tag
          ON tagId = objectTagTagId
        WHERE objectTagObjectType = _objectType
          AND objectTagObjectId = _objectId
          AND objectTagIsDisabled = 0
          AND objectTagIsActive = 1
          AND tagIsDisabled = 0
          AND tagIsActive = 1
      ) as subQuery
    );

  RETURN _outObjectTags;

END $$

DELIMITER ;

调用查询只是：

SELECT fnObjectTagGetObjectTags(3, album.albumId)
FROM album
WHERE fnObjectTagGetObjectTags(3, album.albumId) IS NOT NULL
AND albumIsDisabled = 0
AND albumIsActive = 1

我无法弄清楚为什么会这样做。有人看到奇怪吗？我正在运行5.5.13 感谢

Answer 1

在连接之前尝试将tagId显式转换为字符，因为您可能混合使用二进制和非二进制字符串。喜欢

SELECT (CAST(GROUP_CONCAT(CONCAT(CAST(tagId AS CHAR), '|', tagName) separator '~') AS CHAR(10000) CHARACTER SET utf8))

MYSQL截断了错误的INTEGER值错误

1 个答案: