Question

我在mongo中更新嵌套的json结构时遇到了困难。我正在使用pymongo和Mongoengine-Rest-framework。

由于这个特殊的json具有动态结构并且嵌套很多，所以我选择使用pymongo而不是mongo-engine ORM。

创建，检索和删除操作非常好。我想对更新问题提出一些建议。

让我们考虑一个已存在于mongo中的示例对象：

st1 = {
        "name": "Some_name",
        "details": {
                    "address1": {
                        "house_no": "731",
                        "street": "Some_street",
                        "city": "some_city"
                            "state": "some_state"
                        }
                }
        }

如果我尝试通过在update命令中发送json st2来添加地址2来更新st1，其中_id是更新的条件，

st2 = {
        "details": {
                    "address2": {
                        "house_no": "5102",
                        "street": "Some_street",
                        "city": "some_city"
                            "state": "some_state"
                        }
                }
        }

我在mongo中获得了以下对象st3，

st3 = {
        "name": "Some_name",
        "details": {
                    "address2": {
                        "house_no": " 5102",
                        "street": "Some_street",
                        "city": "some_city"
                            "state": "some_state"
                        }
                }
        }

而不是预期的st4对象。

st4 = {
        "name": "Some_name",
        "details": {
                    "address1": {
                        "house_no": "731",
                        "street": "Some_street",
                        "city": "some_city"
                            "state": "some_state"
                        },
                    "address2": {
                        "house_no": "5102",
                        "street": "Some_street",
                        "city": "some_city"
                            "state": "some_state"
                        }
                }
        }

我的更新命令是：

result = collection.update_one({'_id': id}, doc)

其中

id：文档的_id

doc :(此处）st2

collection：pymongo colllection object

原始JSON深度为6，键是动态的。不同深度需要更新。

Answer 1

首先，将对象更改为更新：

to_update = {
   "house_no": "5102",
   "street": "Some_street",
   "city": "some_city",
   "state": "some_state"
}

然后使用它来更新所需文档的特定部分：

collection.update_one({_id: id}, { '$set': {"details.address2" : to_update} });

Answer 2

使用它来添加地址2：

collection.update（{'_ id'：ObjectId（doc_id）}，{'$ set'：{'details。％s'％ 'address2'：address2}}，upsert = True）

结帐完整代码：

import pymongo
from bson.objectid import ObjectId

data = {"name": "Some_name",
       "details": {"address1": {"house_no": "731", "street": "Some_street", "city": "some_city", "state": "some_state"}}}

address2 = {"house_no": "731", "street": "Some_street", "city": "some_city", "state": "some_state"}

connect = pymongo.MongoClient('192.168.4.202', 20020)
database = connect['my_test']
collection = database['coll']

# # CREATE COLLECTIONS AND INSERT DATA
# _id = collection.insert(data)
# print _id

doc_id = '57568aa11ec52522343ee695'

collection.update({'_id': ObjectId(doc_id)}, {'$set': {'details.%s' % 'address2': address2}}, upsert=True)

PyMongo：JSON密钥在mongo中更新

2 个答案: