我正在制作突围游戏。我有两个类:一个显示砖图像数组的砖类和一个在窗口周围移动球图像的球类。我试图找出当球击中其中一块砖时如何使砖消失。任何帮助将不胜感激。
砖类:
public class Brick {
private URL url;
private Image brick;
Image [][] bricks = new Image[50][3];
public Brick (Breakout bR){
url = bR.getDocumentBase();
brick = bR.getImage(bR.getDocumentBase(),"brick.png");
for(int i =0; i < bricks.length; i++)
for(int j = 0; j < bricks[0].length; j++)
bricks[i][j] = brick;
}
public void update(Breakout bR){}
public void paint(Graphics g, Breakout bR){
brick = bR.getImage(bR.getDocumentBase(),"brick.png");
int imageWidth = imageWidth = bricks[0][0].getWidth(bR);
int imageHeight = imageHeight = bricks[0][0].getHeight(bR);
for (int i = 0; i < bricks.length; i++)
for ( int j =0; j < bricks[0].length; j++)
g.drawImage(brick, i * imageWidth + 5, j* imageHeight + 5, bR);
}
}
球类:
public class Ball {
private int x=355 ;
private int y=200;
private int speed = 8;
private int xVel = -speed;
private int yVel = speed;
private boolean gameOver = false;
private Image ball;
public Ball (Breakout bR){
ball = bR.getImage(bR.getDocumentBase(),"ball.png");
}
public void update(Breakout bR, Paddle p){
x += xVel;
y += yVel;
if (x < 0){
xVel = speed;
}
else if (x > bR.getWidth()){
xVel = -speed;
}
if(y > bR.getHeight()){
gameOver = true;
}
else if (y < 0){
yVel = speed;
}
collision(p);
}
public void collision(Paddle p){
int pX = p.getX();
int pY = p.getY();
int pHeight = p.getImageHeight();
int pWidth = p.getImageWidth();
if (pX<=x && pX+pWidth>=x && pY-pHeight<=y && pY+pHeight>=y){
yVel = -speed;
}
}
public int getX(){
return x;
}
public int getY(){
return y;
}
public void paint (Graphics g, Breakout bR){
g.drawImage(ball,x,y,bR);
if (gameOver){
g.setColor(Color.WHITE);
g.drawString("Game Over", 100,300);
}
}
}
感谢您的帮助:)
答案 0 :(得分:0)
您可以使用Rectangle.intersects()。
为ball和brick类创建一个getBounds()方法。这将创建一个围绕实体的虚拟矩形。
public Rectangle getBounds(){
return new Rectangle(x, y, ballSizeX, ballSizeY);
}
然后检测到碰撞看起来像:
if(ball.getBounds().intersects(brick.getBounds())){
doSomething();
}
如果您需要,请提供更多信息here。