Question

有两个表：旅行和功能

TRIP

id_employee, date_start, date_end, original_function
001, '2016-04-01', '2016-04-30', 010

功能

id_employee, cd_Function, date_start_function, date_end_function
001, 023, '2016-04-04', '2016-04-10'
001, 015, '2016-04-13', '2016-04-25'

我需要生成以下报告：

员工：id_employee

Functions---Days
010-----------12
015-----------11
023-----------07

Answer 1

我认为你基本上想要union all两个表中的行然后进行聚合：

select id_employee, cd_function, sum(days) as days
from ((select id_employee, cd_function,
              datediff(day, date_start_function, date_end_function) + 1 as days
       from function
      ) union all
      (select id_employee, original_function,
              datediff(day, date_start, date_end) + 1 as days
       from trip
      )
     ) ft
group by id_employee;

Answer 2

看起来应该从旅行原始功能的日子减去功能天数

select id_employee, cd_function, sum(days) as days
from
   (select id_employee, original_function as cd_function,
              datediff(day, date_start, date_end) + 1 as days
    from trip
   ) 
   union all
   (select f.id_employee, x.cd_function, x.days             
    from function f
    left join trip t2 on t2.id_employee_id = f.employee_id
    outer apply (
       select f.cd_function, datediff(day, f.date_start_function, f.date_end_function) + 1 as days
       union all
       select t2.original_function as cd_function,  -(datediff(day, f.date_start_function, f.date_end_function) + 1) as days
      ) x
   )
group by id_employee, cd_function;

计算员工在职能中停留的天数

2 个答案: