试图在yii2

Question

我正在尝试使用kartik expandrow。 在PartiesSearch模型的第一级查询是 -

$query = (new Query())->select(['district'])->from('districts');

在ExpartiesSearch Model中的第二级查询是 -

$query = (new Query())->select(['parties_district','parties_partyname'])->from('parties');

index.php中expandrow的代码是 -

[
            //['class' => 'yii\grid\SerialColumn'],
            'class' => 'kartik\grid\ExpandRowColumn',
            'value' => function($model, $key, $index, $column){
                return GridView::ROW_COLLAPSED;
            },
            'detail' => function($model, $key, $index, $column){
                $searchModel = new ExpartiesSearch();
                $searchModel-> parties_district = $model-> district;
                $dataProvider = $searchModel->search(Yii::$app->request->queryParams);

                return Yii::$app->controller->renderPartial('_exparties', [
                    'searchModel' => $searchModel,
                    'dataProvider' => $dataProvider,
                    ]);                   

                },
            ],

我收到错误 -

Trying to get property of non-object

突出显示的错误行是 -

$searchModel-> parties_district = $model-> district;

如果我将PartiesSearch Model中的查询更改为

，则同一段代码可以正常工作

$sql = 'select district from districts';
$query = Districts::findBySql($sql);

但是，我必须以特定格式（从查询生成器派生）编写查询。请帮忙。

Answer 1

在我的测试中：

$query = (new Query())->select(['district'])->from('districts');

将返回数组数组。在这种情况下，您需要使用$ model ['district']。

[
//['class' => 'yii\grid\SerialColumn'],
'class' => 'kartik\grid\ExpandRowColumn',
'value' => function ($model, $key, $index, $column) {
    return GridView::ROW_COLLAPSED;
},
'detail' => function ($model, $key, $index, $column) {
    $searchModel = new ExpartiesSearch();
    $searchModel->parties_district = $model['district'];
    $dataProvider = $searchModel->search(Yii::$app->request->queryParams);

    return Yii::$app->controller->renderPartial('_exparties', [
        'searchModel' => $searchModel,
        'dataProvider' => $dataProvider,
    ]);

},

尝试使用xdebug查看$ model中的确切内容