Question

我正在使用Yii2 Advanced，但出现此错误

Trying to get property 'chnmem_stid' of non-object

$ isMember-> chnmem_stid中的此函数中有错误；

public function actionChannel($id)
{
    $model = $this->findModelUID($id);
    $isMember = AxChnPermission::ChnMember($model->channel_id);

    $memberStt = array(1,2,3);

    if (in_array($isMember->chnmem_stid, $memberStt))
    {
        $dataProviderPost = AxChannelProvider::ContentProviderMember ($model->channel_id);
    }
    else
    {
        $dataProviderPost = AxChannelProvider::ContentProviderGuest ($model->channel_id);
    }

    return $this->render('/channel/_viewPost', [
        'model' => $this->findModelUID($id),
        'isMember' => $isMember,
        'dataProviderPost' => $dataProviderPost,
    ]);
}

函数AxChnPermission :: ChnMember（$ model-> channel_id）;是

public static function ChnMember($chn_id)
{
    $member = ChnMember::findOne(['user_id' => Yii::$app->user->id, 'channel_id' => $chn_id]);
    return $member;
}

所以我只想返回一个结果的函数，“ chnmem_stid”在模型中设置为hasOne

    /**
 * This is the model class for table "chnmember".
 *
 * @property string $member_note
 * @property int $user_id
 * @property int $channel_id
 * @property int $channel_admin
 * @property int $chnmem_stid
 * @property string $chnmem_date
 * @property int $dsh_statut
 *
 * @property Channel $channel
 * @property User $user
 * @property ChnmemberStatut $chnmemSt
 * @property Channel $channelAdmin
 */
  /**
 * @return \yii\db\ActiveQuery
 */




public function getChnmemSt()
{
    return $this->hasOne(ChnmemberStatut::className(), ['chnmem_stid' => 'chnmem_stid']);
}

如果此函数的返回为NULL，则会出现错误

public static function ChnMember($chn_id)
{
    $member = ChnMember::findOne(['user_id' => Yii::$app->user->id, 'channel_id' => $chn_id]);
    return $member;
}

Answer 1

您的函数AxChnPermission::ChnMember()可能返回null（如果请求的记录不存在）。可能是这种情况，因为错误消息指出$isMember不是对象。您需要对此情况进行其他检查：

$isMember = AxChnPermission::ChnMember($model->channel_id);
if ($isMember === null) {
    // throw exception?
}

Yii2试图获取非对象的属性“ chnmem_stid”

1 个答案: