当访问C#中的成员时,`this`关键字是否可选?

时间:2010-09-22 02:07:12

标签: c# .net this member

我注意到如果你在一个类中有一个私有成员,你可以通过引用它的名称在类方法中访问它。您无需说this.memberName,只需memberName即可。那么在成员访问的上下文中this关键字是可选的吗?

当你想澄清范围时,我确实看到它很有用 - 当你有两个同名的变量时。访问会员时是否还有其他理由使用它?

4 个答案:

答案 0 :(得分:12)

是的,它是可选的。您必须使用它的唯一时间是当您有一个隐藏成员变量的局部变量,或者您想要引用indexed property (aka indexer)时。

答案 1 :(得分:1)

您可以选择在实例成员(例如实例方法或属性)中使用this实例成员访问,因为无论何时调用实例方法this(引用当前对象)都会自动传入作为一个不可见的参数。

您无法在静态成员中使用this来访问实例成员...就像您无法在静态方法中使用this.xthis.y(甚至是简单的x和y)或x或y是实例成员的属性。这是因为静态成员调用中未定义this。静态成员属于整个类......它不知道this指的是哪个实例。这是因为当您调用静态方法或属性时,调用的格式为ClassName.MethodName();,因此静态方法不知道对象this将引用什么。

this也不是可选的(必须使用)作为扩展方法的参数列表中的第一个修饰符。实际上this是将静态方法标识为扩展方法的原因。现在this将第一个参数标识为扩展方法正在运行的实例。

    using System;



    class Class_name
    {


        static  string static_variable="static";

        string instance_variable="instance";


        static void Main()
        {

            Class_name object_name = new Class_name();

            Console.WriteLine("Printing out instance and static variables from within Main() body :");

            Console.WriteLine(object_name.instance_variable);
            Console.WriteLine(Class_name.static_variable);

            /* Note that we cannot say either of the following :

                    object_name.static_variable 
                    Class_name.instance_variable


            */

            Console.WriteLine();




            // now lets call the static and instance methods

            object_name.Instance_method(); // Now this is the key call which 
            // passes "this" as an invisible parameter 
            // to the Instance_method. "this" refers to  
            //  object_name


            Class_name.Static_method();//  "this" is NOT passed to Static_method() because now 
            // the call is made on Class_name ... so there is nothing
            // to be represented by "this"


            Console.ReadLine();

        }



        void Instance_method()
        { 

            // here we receive "this" as an invisible parameter referring 
            // to the object on which  Instance_method is called (i.e. object_name)...
            // ... see the Main() method for comments at the call site. 


            Console.Write("Instace method called ... " +
                            "prints out instance variable twice, with and without 'this': ");

            // the following two calls mean exactly the same.

            Console.Write(this.instance_variable);
            Console.WriteLine (instance_variable);



            // one little additional point is that static members are 
            // accessible from within instance members


            Console.WriteLine();

            Console.Write("static variables can also be accessed from within Instance_method: ");
            Console.WriteLine(static_variable);

            Console.WriteLine();
            Console.WriteLine();




        }


        static void Static_method()
        {

            // See the Main() method body for the call Class_name.Static_method()
            // Notice that this method is called on Class_name and not object_name
            // which means that there is no invisibly passed-in "this" parameter available
            // in this method. 

            // we can also not access the instance_variable in this method 
            // as instance variables are always part of some object. This method
            // is not called on any object, its called on Class_name.

            // Console.WriteLine(instance_variable); // Compiler error

            Console.WriteLine("Static method called ... prints out static variable: ");
            Console.WriteLine(static_variable);




        }






    }

答案 2 :(得分:0)

是的,'这个'是隐含的。它有时可以帮助澄清。而且调用方法也需要引用当前的类。

答案 3 :(得分:0)

当你调用当前类的成员时,“this”几乎总是可选的。

但是,它用于其他目的,例如将当前类实例作为参数传递或将属性,字段或变量设置为当前实例。

您必须使用它来调用方法的唯一情况是您调用扩展方法时:

class AClass {
    void CallIt() {
        Test();                     //not valid
        this.Test();                //valid 
    }
}
static class AnExtension {
    public static void Test(this AClass source) {

    }
}