Question

如何确保每次在python中返回的值都是唯一的？我正在使用random.randrange如此 -

batter = ("Sammy Slammer","Lonnie Longball","Billy Bomber","Jack Runs","Ricky Redic",)
bnum = random.randrange(0,5)
upnow = batter[bnum]

除了经常重复之外，哪些有效..

感谢@Fabricator -

batter = ("Sammy Slammer","Lonnie Longball","Billy Bomber","Jack Runs","Ricky Redic",)
bnum = random.randrange(0,5)
upnow = batter[bnum]
l = list(batter)
random.shuffle(l)
for upnow in l:
print upnow

和 -

batter = ("Sammy Slammer","Lonnie Longball","Billy Bomber","Jack Runs","Ricky Redic",)
l = list(batter)
random.shuffle(l)
for upnow in l:
print upnow

错误即时反馈我的sqlite 3声明 -

＆＃34;对于i在reverse（xrange）1中，len（x）int没有len（）＆＃34;

我缩短了代码，sqlite3在没有随机播放的情况下工作正常。

    bbatter_ai =  (brow["BATTER"])
tab = cab_ai + at_bat
conn.execute("UPDATE batter set AB = ? WHERE BATTER = ?",[tab] + [bbatter_ai])

Answer 1

你可以随机播放玩家名单：

l = list(batter)
random.shuffle(l)
for upnow in l:
    print upnow

IDLE：

In [1]: import random

In [2]: batter = ("Sammy Slammer","Lonnie Longball","Billy Bomber","Jack Runs","Ricky Redic",)

In [3]: l = list(batter)

In [4]: random.shuffle(l)

In [5]: for upnow in l:
   ...:     print upnow
   ...:     
Jack Runs
Sammy Slammer
Lonnie Longball
Billy Bomber
Ricky Redic

python randrange重复选择

1 个答案: