JAVA - Hangman游戏，保持在未知字母中输入正确的字母

Question

 if(letterGuessBoolean == true) {
      System.out.println("Nice job! That was correct!");
      for (position = 0; position < pickRandomWord.length(); position++) {
        if (pickRandomWord.charAt(position) == letterGuess) {
          System.out.print(letterGuess);
        } 
        else {
          System.out.print(unknownLetters);
        }
      }
    }

循环会正确保存单词，未知字符永远不会保存正确的方式。

Answer 1

您只打印出最新猜测的信件，因为这是您唯一要检查的信件：

pickRandomWord.charAt(position) == letterGuess

你需要记住以某种方式和某个地方，以前猜过哪些字母。一种变体可能如下：

String pickRandomWord = ""; // select your random word
char[] displayOutput = new char[pickRandomWord.length()];
for(int n = 0; n < displayOutput.length; ++n)
    displayOutput[n] = '-';

/* ... */

if(letterGuessBoolean) // do not compare against true, if it is already boolean!
{
    for(int position = 0; position < pickRandomWord.length(); ++position)
    {
        if (pickRandomWord.charAt(position) == letterGuess)
        {
            displayOutput[position] = letterGuess;
        }
        System.out.print(displayOutput[position]);
    }
}