如何从python模块访问自定义异常处理程序？

Question

这些是我的文件：

myModule/__init__.py

import sys

class MyModule:
  handle_exceptions = handle_exceptions
  def __init__(self):
    sys.excepthook = handle_exceptions

#myModule/handle_exceptions.py
def handle_exceptions(ex_cls, ex, tb):
  #not important here      
  pass


#my_script.py
import sys
import myModule
sys.excepthook = myModule.handle_exceptions

＆＃39; handle_exceptions＆＃39;的内容在这里并不重要，因为我根本无法访问它。

Traceback (most recent call last):
 File "my_script.py", line 2, in <module>
    import myModule
 File "D:\Python34\myModule\__init__.py", line 3, in <module>
    class MyModule:
 File "D:\Python34\myModule\__init__.py", line 4, in MyModule
    handle_exceptions = handle_exceptions
 NameError: name 'handle_exceptions' is not defined

Answer 1

试试这个

myModule/__init__.py
import sys

class MyModule:
  def __init__(self):
    sys.excepthook = handle_exceptions
    self.handle_exceptions = handle_exceptions


#myModule/handle_exceptions.py
def handle_exceptions(ex_cls, ex, tb):
  #not important here
  pass




import sys
from myModule import handle_exceptions
sys.excepthook = handle_exceptions