Question

我有两张桌子：

table1
id | mcc | mnc | active | client_id
1    202   05      1        4
2    202   06      0        4 
.......a lot

table2
id | mcc | mnc | rejectReason
1    202   05         null
2    202   06         null

需要插入到table2中，但需要检查table1的每个项目，以便插入table2：

 SELECT table1 t1

(CASE WHEN t2.id != 0
THEN
  INSERT INTO table2 t22
  SET (
       t22.rejectReason = CONCAT('LOSS OF COVERAGE'),
       t22.mcc = t1.mcc,
       t22.mnc = t1.mnc,
  )
 WHERE t22.mcc     = t1.mcc
 AND   t22.mnc     = t1.mnc
 ELSE
   ''
END)

 LEFT JOIN table2 t2
 ON  t2.mcc       = t1.mcc
 AND t2.mnc       = t1.mnc

如果table1没有像table2这样的项目（mcc / mnc），那么为table2插入当前项目。请帮忙

RESULT:

＆＃13;

 table1
    id | mcc | mnc | active | client_id
    1    202   05      1        4
    2    202   06      0        4 
    3    214    0      1        5
    .....
         212    16     // not exist 
         214    07     // not exist 
    .......a lot
    
    table2
    id | mcc | mnc | rejectReason
    1    202   05         null
    2    202   06         null
    3    212   16         LOSS OF COVERAGE // then insert 
    4    214   07         LOSS OF COVERAGE // then insert

＆＃13;

Answer 1

嗯，我不太明白你想要什么，但这是一个应该如何的结构，根据你的意思调整它：

UPDATE table2 t2
LEFT JOIN table1 t1
 ON(t1.mcc = t2.mcc and t1.mnc = t2.mnc)
SET t2.rejectReason = 'LOSS OF COVERAGE'
WHERE t1.id is null

这会将t2.rejectReason更新为“覆盖范围内”＆＃39;当表1中没有相同mcc,mnc的记录时。顺便说一下，CONCAT()用来联合多于1个字符串，你也有一个字符串，所以你不需要它。 / p>

编辑：如果您想要插入，那么：

INSERT INTO table2
SELECT t.id,t.mcc,t.mnc,'LOSS OF COVERAGE'
FROM Table1 t
WHERE NOT EXISTS(SELECT 1 from table2 s
                 WHERE t.mcc = s.mcc and t.mnc = s.mnc)

EDIT2：我不知道这个错误，所以可能更容易解决，但你可以这样做：

CREATE TABLE Temp_Tbl AS
(SELECT t.id,t.mcc,t.mnc,'LOSS OF COVERAGE'
FROM Table1 t
WHERE NOT EXISTS(SELECT 1 from table2 s
                 WHERE t.mcc = s.mcc and t.mnc = s.mnc));

INSERT INTO Table2
SELECT * FROM Temp_Tbl;

DROP TABLE Temp_Tbl;

如何通过联合其他表插入一个表？

1 个答案: