如何通过使用引用将选定的字段插入到另一个表中,以便只插入一行数据?
到目前为止,我只能在phpmyadmin
中使用语句时获取所有传输的字段$Reference=$_GET['Reference'];
$sql="INSERT INTO Triage (Reference, Forename)
SELECT Reference, Forename from `Instruction` WHERE Reference='$Reference'"
答案 0 :(得分:0)
INSERT INTO Table2(LongIntColumn2,CurrencyColumn2) 选择LongIntColumn1,Avg(CurrencyColumn)作为CurrencyColumn1 FROM Table1 GROUP BY LongIntColumn1;
INSERT INTO prod_detail(prod_name,prod_code)选择Name,Zip作为来自info_tb的数据,其中Name =" mittal&#34 ;;
答案 1 :(得分:0)
尝试这样的事情:
$Reference=mysql_real_escape_string($_GET['Reference']);
$sql="INSERT INTO Triage (Reference, Forename)
SELECT Reference, Forename FROM `Instruction`
WHERE Reference='$Reference' LIMIT 1";