Question

您好我必须执行一个程序来识别列表中出现单词的所有位置，但是当我运行程序时它不会输出任何内容。这是我的代码：

sentence =("ASK NOT WHAT YOUR CONTRY CAN DO FOR ASK WHAT YOU CAN DO FOR YOUR CONTRY") #This is a list
print (sentence)
text = input("Choose a word from the sentence above")#this prints out some text with an input 
sentence = sentence.split(" ")# This splits the list 
text = text.upper ()# this makes the text in capital letters
def lookfor ():
    if text in sentence:
        for i in sentence:
            value = sentence.index(sentence)
            print ("Your word has been found in the sentence at the position", value + "and", value )


        else:
            print ("The word that you have typed is not found in the sentence.")

谢谢

Answer 1

要回答你的问题，没有任何事情发生，因为你没有调用这个功能。

您的功能还有很多工作要做，但这里有一些常规提示：

1）索引只查找列表中元素的第一个实例

2）你无法确定句子中的单词是否正好两次

3）使用描述性变量名称。例如，for word in sentence在直觉上更有意义

Answer 2

您可以这样做：

sentence =("ASK NOT WHAT YOUR CONTRY CAN DO FOR ASK WHAT YOU CAN DO FOR YOUR CONTRY") #This is a list
print (sentence)
text = raw_input("Choose a word from the sentence above: ")#this prints out some text with an input 
sentence = sentence.split(" ")# This splits the list 

text = text.upper ()# this makes the text in capital letters
def lookfor (text):
    indexes = [ idx+1 for word, idx in zip(sentence, range(0,len(sentence))) if text == word ]
    print ("Your word has been found in the sentence at these positions", indexes )

    if not indexes:
         print ("The word that you have typed is not found in the sentence.")

lookfor(text)

示例：

ASK NOT WHAT YOUR CONTRY CAN DO FOR ASK WHAT YOU CAN DO FOR YOUR CONTRY
Choose a word from the sentence above: for
('Your word has been found in the sentence at these positions', [8, 14])

Python在列表中查找单词

2 个答案: