Question

我试图制作过滤器机器人，可以在阻止列表中列出的消息中找到相同的字符或相同的单词

block = ["damn", "shit"]

如果消息计数：daaaaammmmnnnn或sssssshit或da-mn或da.mn.像抓住它并返回True

我该怎么办呢。

THX。

Answer 1

当邮件包含列表flag中的任何项目时，将True值设置为block。

获取block列表并按for循环遍历列表中的每个项目。
默认情况下，将flag设置为False表示邮件不包含任何阻止列表项。
当邮件中的flag列表中的项目时，将True设置为block。
使用break语句停止for循环迭代。

e.g。

>>> block = ["damn", "shit"]
>>> msg = "test masf to check shit or damn"
>>> flag = False
>>> for i in block:
...   if i in msg:
...      flag = True
...      break
... 
>>> flag
True
>>>

更新：

设置block列表单词。
创建阻止列表字符列表的列表。
从输入字符串中删除标点符号。
将字符串拆分为单词。
拆分单词并从单词创建字符序列列表。
检查阻止列表字符列表中的字符序列列表。

代码：

import string
block = ["damn", "shit"]
block_char_list = [ list(i) for i in block ]

def  getbBlockListFlag(msg):
    #Remove punctuation
    tmp = msg.translate(string.maketrans("",""), string.punctuation)
    tmp1 = []
    for word in tmp.split():
        j = []
        for k in list(word):
            if k not in j:
                j.append(k)
            elif k != j[-1]:
                j.append(k)

        # word in block list
        if j in block_char_list:
            return True, j

    return False, []



msg = "True test case ? daaaammmmnnnnn.,"
status, block_char = getbBlockListFlag(msg)
if status:  
    print "The word `%s` from block list is presnt in input '%s'"%(''.join(block_char), msg)
else:
    print "No word from block list is presnt in input '%s'"%(msg)

msg = "True test case ? normal damn.,"
status, bloak_char = getbBlockListFlag(msg)
if status:  
    print "The word `%s` from block list is presnt in input '%s'"%(''.join(block_char), msg)
else:
    print "No word from block list is presnt in input '%s'"%(msg)

msg = "False test case ? nothing when sequance aaammdddnnn.."
status, bloak_char = getbBlockListFlag(msg)
if status:  
    print "The word `%s` from block list is presnt in input '%s'"%(''.join(block_char), msg)
else:
    print "No word from block list is presnt in input '%s'"%(msg)


msg = "False test case ? nothing.."
status, bloak_char = getbBlockListFlag(msg)
if status:  
    print "The word `%s` from block list is presnt in input '%s'"%(''.join(bloak_char), msg)
else:
    print "No word from block list is presnt in input '%s'"%(msg)
msg = "True test case ? Handle  daaaammaaaammnnnnn.,"
status, block_char = getbBlockListFlag(msg)
if status:  
    print "The word `%s` from block list is presnt in input '%s'"%(''.join(block_char), msg)
else:
    print "No word from block list is presnt in input '%s'"%(msg)

输出：

vivek@vivek:~/Desktop/stackoverflow$ python 16.py 
The word `damn` from block list is presnt in input 'True test case ? daaaammmmnnnnn.,'
The word `damn` from block list is presnt in input 'True test case ? normal damn.,'
No word from block list is presnt in input 'False test case ? nothing when sequance aaammdddnnn..'
No word from block list is presnt in input 'False test case ? nothing..'
No word from block list is presnt in input 'True test case ? Handle  daaaammaaaammnnnnn.,'

Answer 2

from collections import OrderedDict

string = "test this string to check for sshh-iitit and dammm.mn"
new_string = string.replace('-','')
final_string = new_string.replace('.','')
words = final_string.split()
for word in words:
    check = "".join(OrderedDict.fromkeys(word))
    if check == "damn" or check == "shit":
        print "true"

Answer 3

你应该看一下Levenshtein distance！ PHP有一个很好的函数叫做leventhstein（）。而对于Phython来说，最少有一个C实现：https://pypi.python.org/pypi/python-Levenshtein/0.12.0

在列表中找到类似的单词

3 个答案: