Postgres:加入两个查询并根据结果进行选择

时间:2016-05-25 08:16:33

标签: sql postgresql subquery inner-join

有一个社交网络,每个用户都可以重新发布其他用户的帖子。你的帖子每10个转发你得到一份礼物。有两个表:giftsrepost_history,请参阅下面的方案。

问题: 如何编写一个查询来计算系统中每个用户需要多少礼物?

=========
= gifts =
=========
   id       // PK
 user_id    // id of user which received a gift
 amount     // amount of gifts (bonuses), may be + or -
  type      // type of a gift.  The only type we're interested in is 'REPOST_TYPE'

==================
= repost_history =
==================
      id     // PK
    user_id  // id of a user which did repost
    owner_id // id of a user whose post was reposted

查询算法:

1)查找每个用户的总转发次数 SELECT owner_id, COUNT(owner_id) FROM repost_history GROUP BY owner_id;

2)查找每位用户的REPOST_TYPE份礼物总额  SELECT user_id, COUNT(amount) FROM gifts WHERE type = 'REPOST_TYPE' GROUP BY user_id;

3)根据owner_id = user_id

加入第1步和第2步

4)来自基于第3步结果的(user_id,gift_to_grand_count)结果集。 <gift_to_grand_count> = (<reposts_of_user> / 10) - <user_repost_gifts_amount>

的位置

我的解决方法: 1-3步骤实现(不工作,因为我不知道如何将子查询结果设置为变量)。如何使它工作并做第4步?

(
  SELECT owner_id, COUNT(owner_id) AS reposts_count
  FROM reposts_history
  GROUP BY owner_id 
  AS user_reposts
)   
INNER JOIN (
  SELECT user_id, COUNT(amount) AS gifts_count
  FROM gifts 
  WHERE type = 'REPOST_GIFT' 
  GROUP BY user_id 
  AS user_gifts
) 
ON user_reposts.owner_id = user_gifts.user_id

数据样本:

为简单起见,我们假设我们想要在每个第3个转贴(而不是每个第10个转发)上赠送礼物

礼物 - 您可以看到user_id=1已获赠1件REPOST_TYPE礼物。我们对他花了多少礼物不感兴趣。

id | user_id | amount |     type      |
 1 |    1    |    1   | 'REPOST_TYPE' |
 2 |    1    |    2   | 'OTHER_TYPE'  |
 3 |    1    |   -1   | 'REPOST_TYPE' |
 4 |    2    |    1   | 'REPOST_TYPE' |

reposts_history - 您可以看到其他用户重新发布了用户owner_id=1 6次。

id  | user_id | owner_id | another columns...
 1  |    2    |    1     |
 2  |    3    |    1     |
 3  |    4    |    1     |
 4  |    5    |    1     |
 5  |    2    |    1     |
 6  |    6    |    1     |
 6  |   13    |    2     |

所以user_id=1应该获得<total_reposts> / 3 - <already_granted_gifts_amount> = 6 / 3 - 1 = 1个礼物。

我想获得系统中的所有用户:

user_id | gifts_to_grant |
   1    |       1        |
   2    |       0        |
     ..........

1 个答案:

答案 0 :(得分:1)

您需要一个外部联接,以便找到值得赠送但尚未收到礼物的用户:

select
  b.ownerid as userid, 
  b.rebets_count, 
  b.rebets_count / 10 as gifts_expected, 
  coalesce(g.gifts_count, 0) as gifts_received,
  b.rebets_count / 10 - coalesce(g.gifts_count, 0) as gifts_missing 
from
(
  select owner_id, count(*) as rebets_count
  from bets 
  group by owner_id 
) b  
left join 
(
  select user_id, count(*) as gifts_count
  from gifts 
  where type = 'REBET_GIFT' 
  group by user_id 
) g on g.user_id = b.owner_id;