我有3个postgresql表如下
员工
emp_name | emp_id | user_name | psw | etc
工作
Work_id |work_type| Project_manger_id(employee) | Architect_id (emp) | tech_lead_id | dept_id
dept
dept_id | dept_name
现在我想要的是像这样的表
work_type | project_manager (name) | architect (name) | tech_lead (name ) | dept (name )
简单地说,我想要的是获取工作表,但用名称
替换id答案 0 :(得分:3)
试试这个
Select WT.Work_Type,PM.emp_name As ProjectManager,AR.emp_name AS Arhitect,TL.emp_name As TechLead,Dept.Dept_name As Department From
Work
INNER JOIN employees AS PM ON (Wt.Project_manger_id=PM.emp_id)
INNER JOIN employees AS AR ON (Wt.Architect_id=AR.emp_id)
INNER JOIN employees AS TL ON (Wt.tech_lead_id=TL.emp_id)
INNER JOIN Dept As Dept ON (Wt.dept_id=Dept.dept_id)