Question

我有一张表格。当用户提交时，值应插入数据库中。只有一个$ _POST的值没有插入数据库中，但其他$ _POST正在正确插入。

如何解决这个问题？

HTML：

<input type="text" name="position" value="<?php echo $_POST['jobTitle']; ?>" id="position" required/>

PHP代码段：

$firstName = $middleName = $lastName = $email = $mobile = $resume = $position = $message = $attachment_id = $locations = "";

if(isset($_POST['submit'])){
    $firstName = isset($_POST['firstName']) ? $_POST['firstName'] : '';
    $middleName = isset($_POST['middleName']) ? $_POST['middleName'] : '';
    $lastName = isset($_POST['lastName']) ? $_POST['lastName'] : '';
    $email = isset($_POST['email']) ? $_POST['email'] : '';
    $mobile = isset($_POST['mobile']) ? $_POST['mobile'] : '';
    $locations = isset($_POST['locations_list']) ? $_POST['locations_list'] : '';
    $position = isset($_POST['jobTitle']) ? $_POST['jobTitle'] : '';
    $message = isset($_POST['message']) ? $_POST['message'] : '';
        if( ! empty($_FILES)){
            $file=$_FILES['resumeFile'];
            $attachment_id = upload_user_file($file);
        }

    $sql=$wpdb->query("INSERT INTO resume_databank(submit_time,last_name,first_name,middle_name,mobile_number,email,location,position,message,process_resume,attachment_resume_id) VALUES (now(),'$lastName','$firstName','$middleName','$mobile','$email','$locations','$position','$message','No','$attachment_id')");
}

exit();

Answer 1

更改此部分

$position = isset($_POST['jobTitle']) ? $_POST['jobTitle'] : '';

到

$position = isset($_POST['position']) ? $_POST['position'] : '';

因为在你的表格中。您的字段名称为position，$_POST['jobTitle'];只是一个值

$ _POST不在数据库中插入值

1 个答案: