Question

我想将以下XML文档发送到我的Web Api 2控制器;但是，[FromBody]参数始终为空。

这是请求XML正文：

<razorInbound server="PortfolioExposureServer" request="lookupRiskPointRecord">
  <caller>RazorClient</caller>
  <responseMode>xml</responseMode>
  <body>
    <conditions>
      <fromOffset>0</fromOffset>
      <top>100</top>
      <condition>
        <keyPath>
          <keyElement nodeOffset='1'>Currency</keyElement>
          <keyElement nodeOffset='2'>ID</keyElement>
        </keyPath>
        <lookupValue>USD</lookupValue>
      </condition>
    </conditions>
  </body>
</razorInbound>

使用Postman发送请求，如下：

POST /api/razorXmlRequest HTTP/1.1
Host: localhost:5000
Content-Type: application/xml
Cache-Control: no-cache
Postman-Token: 6ca91ebf-31e0-77f2-6f81-cb9993b69b1a

<razorInbound server="PortfolioExposureServer" request="lookupRiskPointRecord">
  <caller>RazorClient</caller>
  <responseMode>xml</responseMode>
  <body>
    <conditions>
      <fromOffset>0</fromOffset>
      <top>100</top>
      <condition>
        <keyPath>
          <keyElement nodeOffset='1'>Currency</keyElement>
          <keyElement nodeOffset='2'>ID</keyElement>
        </keyPath>
        <lookupValue>USD</lookupValue>
      </condition>
    </conditions>
  </body>
</razorInbound>

Web Api 2控制器：

注意：param参数始终为null

我相信我需要一个合适的类定义才能正确映射XML请求，但我不确定如何构建它。

using System;
using System.Threading.Tasks;
using System.IO;
using System.Text;
using RazorServices;
using System.Net.Http;
using System.Web.Http;
using System.Xml.Linq;
using System.Net;
using System.Xml;

namespace RazorWebApi.Controllers
{
    [Route("api/razorXmlRequest")]
    public class RazorXmlRequestController : ApiController
    {
        public class RawXml {
            public string RazorXml { get; set; }
        }

        [HttpPost]
        public async Task<HttpResponseMessage> Post([FromBody]RawXml param )
        {
            HttpResponseMessage resp = new HttpResponseMessage(HttpStatusCode.OK);

            // code omitted...
			
            return resp;
        }
    }
}

顺便说一句，我们目前正在通过设置StreamReader对象来解决此问题，以便从this.Request.Content获取;但是在我的单元测试中，我需要发送我的xml作为参数。

[HttpPost]
        public async Task<HttpResponseMessage> Post()   // [FromBody]RawXml param )
        {
            HttpResponseMessage resp = new HttpResponseMessage(HttpStatusCode.OK);

            StreamReader sr = new StreamReader(await this.Request.Content.ReadAsStreamAsync(), Encoding.UTF8);
            string xml = sr.ReadToEnd();

            if (xml == null || xml.Length < 4)
            {
                throw new RazorServicesException("Invalid XML");
            }
            RazorSession cred = RzWebApi.Cred;
            string reply = await RzWebApi.RazorSrv.xmlRequests.Request(cred, xml);
            resp.Content = new StringContent(reply, System.Text.Encoding.UTF8, "text/plain");
            return resp;
        }

Answer 1

最终解决方案是将Post param类型更改为XElement：

[Route("api/razorXmlRequest")]
public class RazorXmlRequestController : ApiController
{
    /// <summary>
    /// Raw Razor request XML 
    /// </summary>
    /// <returns>Razor reply message as text</returns>
    [HttpPost]
    public async Task<HttpResponseMessage> Post([FromBody]XElement xml)
    {
        HttpResponseMessage resp = new HttpResponseMessage(HttpStatusCode.OK);
        RazorSession cred = RzWebApi.Cred;
        string reply = await RzWebApi.RazorSrv.xmlRequests.Request(cred, xml);
        resp.Content = new StringContent(reply, System.Text.Encoding.UTF8, "application/xml");
        return resp;
    }
}

这甚至没有按照绅士们上面的建议提供XmlFormatter（@TusharJ，无论如何，谢谢你的意见）。

Answer 2

您可以将XmlSerializer配置为使用WebApiConfig.Register的Web API，如下所示;

config.Formatters.XmlFormatter.UseXmlSerializer = true;

通过http Post请求向Web Api发送XML的问题

2 个答案: