Question

我正在尝试使用java登录网站，然后最终检索cookie以获取对网站信息的访问权限。似乎我的帖子请求正在运行，但我收到500的响应代码。我想知道这是因为我的帖子数据格式不正确

使用网站时，帖子的格式如下

{userName: "dfh", password: "suyj"}

在我的代码中，我使用了这个

String urlParameters = "userName:dfh,Password:suyj";

    con.setDoOutput(true);
    DataOutputStream wr = new DataOutputStream(con.getOutputStream());
    wr.writeBytes(urlParameters);
    wr.flush();
    wr.close();

我是否正确地认为这可能是问题，如果是，我该如何更正我的帖子数据格式？

以下是我的整个代码

public  class post {
public static void main(String[] args) throws IOException {
final String USER_AGENT = "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:31.0) Gecko/20100101 Firefox/31.0";


    String url = "website";
    URL obj = new URL(url);
    HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();

    //add reuqest header
    con.setRequestMethod("POST");
    con.setRequestProperty("User-Agent", USER_AGENT);
    con.setRequestProperty("Accept", "application/json, text/javascript, */*; q=0.01");
    con.setRequestProperty("Accept-Language", "en-US,en;q=0.5");
    con.setRequestProperty("Accept-Encoding", "gzip, deflate");
    con.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
    con.setRequestProperty("X-Requested-With", "XMLHttpRequest");
    con.setRequestProperty("Referer", "https://extbasicph05.podc.sl.edst.ibm.com/FFAMobileRelay/");
    con.setRequestProperty("Content-Length", "64");
    con.setRequestProperty("Connection", "keep-alive");
    con.setRequestProperty("Referer", "https://extbasicph05.podc.sl.edst.ibm.com/FFAMobileRelay/");
    con.setRequestProperty("Cookies", "UnicaNIODID=KGew34gcvZ5-Y2NoBQr; mmid=-1658088866%7CKAAAAAr15Tc8FgsAAA%3D%3D; mmcore.pd=1484641984%7CejEyAAoBQvXlNzwWCxPPXGheAVibftSXgNJIDwAAADoOVvoDstFIAAAAAP//////////AAZEaXJlY3QBFgwIAAYABQAAAAAAAP+MAACAigAA/4wAAAIAxDEAAABFBVUW6QsA/////wHpCxoM//83AAAAAAAAAAOSfwAAusgAAJN/AAAgyAAAlH8AACHIAAABIYAAAAIAAADVNgAAAPcCB+70CwD/////AfQLHQz//60CAAEAAAAAAX+KAAAp2gAAAoCKAABAWBAAgYoAALMAAAAAAAABRQ%3D%3D; mmcore.srv=ldnvwcgus03; IBM_W3SSO_ACCESS=w3-03.sso.ibm.com; CoreID6=32675392371714128784599&ci=51040000|IBMTEST_51040000|IBMTESTW3_50200000|IBMTESTWWW; CoreM_State=75~-1~-1~-1~-1~3~3~5~3~3~7~7~|~~|~~|~~|~||||||~|~~|~~|~~|~~|~~|~~|~~|~; CoreM_State_Content=6~|~EE9EDB09923CD77F~|~0; PrefID=222-11978519; CSList=23427744/17540903,0/0,0/0,0/0,0/0; _ga=GA1.2.233924805.1433836377; mmcore.tst=0.169; ibmSurvey=1435758135373; 50200000_clogin=v=1&l=1435758136&e=1435760174616");

    String urlParameters = "userName:dfh,Password:suyj";

    // Send post request
    con.setDoOutput(true);
    DataOutputStream wr = new DataOutputStream(con.getOutputStream());
    wr.writeBytes(urlParameters);
    wr.flush();
    wr.close();

    int responseCode = con.getResponseCode();
    System.out.println("\nSending 'POST' request to URL : " + url);
    System.out.println("Post parameters : " + urlParameters);
    System.out.println("Response Code : " + responseCode);
    System.out.println(con.getErrorStream());

    BufferedReader in = new BufferedReader(
            new InputStreamReader(con.getInputStream()));
    String inputLine;
    StringBuffer response = new StringBuffer();

    while ((inputLine = in.readLine()) != null) {
        response.append(inputLine);
    }
    in.close();

    //print result
    System.out.println(response.toString());

}

}

Answer 1

您已经发现了问题所在。只是解决它... 而不是String urlParameters = "userName:dfh,Password:suyj";，请使用

String urlParameters = "{userName:\"dfh\",Password:\"suyj\"}";

虽然我相信你的服务器需要JSON格式的post参数。在这种情况下，你应该使用，

String urlParameters = "{\"userName\":\"dfh\",\"Password\":\"suyj\"}";

或使用JSON解析器创建参数。

向网站发送帖子请求

1 个答案: