我遇到了这些在hmatrix中表现奇怪的标量和矩阵的奇怪情况。如果我没有输入注释,那么该操作将自动运行ala matlab / python。但是如果我用“R”或类型或“Double”键入标注标量,我会收到类型错误。
为什么会这样?
λ> 4 + ([1,2,3] :: Vector R)
[5.0,6.0,7.0]
λ> (4 :: R) + ([1,2,3] :: Vector R)
<interactive>:155:14:
Couldn't match type ‘Vector R’ with ‘Double’
Expected type: R
Actual type: Vector R
In the second argument of ‘(+)’, namely ‘([1, 2, 3] :: Vector R)’
In the expression: (4 :: R) + ([1, 2, 3] :: Vector R)
In an equation for ‘it’: it = (4 :: R) + ([1, 2, 3] :: Vector R)
λ> (4 :: Double) + ([1,2,3] :: Vector R)
<interactive>:156:19:
Couldn't match expected type ‘Double’ with actual type ‘Vector R’
In the second argument of ‘(+)’, namely ‘([1, 2, 3] :: Vector R)’
In the expression: (4 :: Double) + ([1, 2, 3] :: Vector R)
In an equation for ‘it’:
it = (4 :: Double) + ([1, 2, 3] :: Vector R)
λ> (4 :: R) * ([1,2,3] :: Vector R)
<interactive>:157:14:
Couldn't match type ‘Vector R’ with ‘Double’
Expected type: R
Actual type: Vector R
In the second argument of ‘(*)’, namely ‘([1, 2, 3] :: Vector R)’
In the expression: (4 :: R) * ([1, 2, 3] :: Vector R)
In an equation for ‘it’: it = (4 :: R) * ([1, 2, 3] :: Vector R)
λ> 4 * ([1,2,3] :: Vector R)
[4.0,8.0,12.0]
λ>
答案 0 :(得分:2)
我认为记录在案here
自动整形尺寸
在大多数操作中,单元素向量和矩阵(从 数字文字或使用标量),以及只有一行或的矩阵 列,自动展开以匹配另一个的尺寸 操作数
你必须匹配类型和大小,你的注释类型是标量,但期望在第二个操作数中有一个向量。