我一直在尝试使用ggnet2
绘制图表。为此,我使用以下代码:
library(igraph)
lapply(c("sna", "intergraph", "GGally", "igraph", "network"), require, character.only=T)
data <- read.table('CA-CondMat.txt',sep="\t",header=TRUE)
g = graph.data.frame(data, directed = TRUE)
N = vcount(g)
E = ecount(g)
perc = 0.1
d.g = degree(g,mode='all')/N
new_nodes = sample.int(N,ceiling(perc*N),replace=FALSE,prob =d.g)
new_g = subgraph(g,new_nodes)
dg = degree(g,mode='all')
prob = dg/sum(dg)
png('example_plot2.png')
ggnet2(new_g, size = "degree", node.color = "steelblue", size.cut = 4,
edge.size = 1, edge.color="grey" )
dev.off()
我得到一张完全蓝色的图表。
我正在使用包igraph
。
我想要绘制的是一个图表,节点的颜色基于它们的程度,如下所示:
链接到文件:
https://snap.stanford.edu/data/ca-CondMat.html
修改
添加完整示例
答案 0 :(得分:7)
我很欣赏挑战,图表总是很有趣。我认为这就是你想要的(我修改了我的原文以使用你之后提供的文件):
在我的代码中clr-degree
是学位的一半,因为这个文件只有对称链接,如果没有黑色和绿色节点,它看起来很无聊。
我还为所有调用添加了库前缀,这样我就可以看到从什么网络库(igraph,网络等)中使用了什么。这些库中存在大量重叠和相互依赖。
请注意,此代码应将0-1
映射到black
到2
,将red
映射到3
,将green
映射到>=4
}和red
到library(ggplot2)
library(igraph)
library(GGally)
# the following libraries will be required too - used internally
lapply(c("sna", "scales","intergraph", "network"),require, character.only=T)
set.seed(1234)
# data from https://snap.stanford.edu/data/ca-CondMat.html
data <- read.table('CA-CondMat.txt',sep="")
g = igraph::graph.data.frame(data, directed = TRUE)
N = vcount(g)
E = ecount(g)
d.g = igraph::degree(g,mode='all')/N
# Use new smaller subgraph
perc = 0.05
new_nodes = sample.int(N,ceiling(perc*N),replace=FALSE,prob =d.g)
new_g = igraph::subgraph(g,new_nodes)
dg = igraph::degree(new_g,mode='all')
dg <- dg/2 # for some reason there are only even degrees in this file - so we divide by 2
clrvek = pmax(0,pmin(dg,4))
clrnames = c("0"="lightgrey","1"="black", "2"="blue", "3"="green", "4"="red")
#png('example_plot2.png')
GGally::ggnet2(new_g,
color.legend="clr-degree",palette=clrnames,color=clrvek,
size = "degree",
edge.size = 1, edge.color="grey",
legend.position = "bottom") + coord_equal()
#dev.off()
:
String output = "";
for (int i = 0; i < NumberOfSlot; i++) {
output = Math.random() * 10 <= 5 ? output+"R" : output+"L";
}
JOptionPane.showMessageDialog(null, output);
//edited the answer according to op's last comment.
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