Question

我准备了以下代码：

public static void main(String[] args) {
Scanner inChoice = new Scanner(System.in);

while(true)
        {
            try
            {
                System.out.println("--------------------------------------------------------");
                System.out.println("Make your choice :");
                System.out.println("For integer - CHOOSE 1");
                System.out.println("For floating-point numbers - CHOOSE 2");
                intChoice = inChoice.nextInt();
                break;
            }
            catch (InputMismatchException imex)
            {
                System.out.println("You have made a wrong selection. Try again");
                continue;
            }
        }
}

问题是当我选择其他东西然后是整数（例如'w'）。我的目的是给出一个在例外后再次选择的机会。但相反，我的代码会无限地捕获阻塞和循环并给我消息：

"--------------------------------------------------------"
"Make your choice :"
"For integer - CHOOSE 1"
"For floating-point numbers - CHOOSE 2"
"You have made a wrong selection. Try again"


"--------------------------------------------------------"
"Make your choice :"
"For integer - CHOOSE 1"
"For floating-point numbers - CHOOSE 2"
"You have made a wrong selection. Try again"


"--------------------------------------------------------"
"Make your choice :"
"For integer - CHOOSE 1"
"For floating-point numbers - CHOOSE 2"
"You have made a wrong selection. Try again"

结束......

它没有给我机会再次选择。有人可以解释我，我做错了什么？感谢

Answer 1

发生异常时，不会消耗输入。它留在那里。你需要消耗它，否则它将继续抛出异常。

您只需在异常块中添加此行（当然在continue之前）：

inChoice.next();

无限循环在java中异常

1 个答案: