Question

while循环应该比较这两个对象的ibsn。被比较的对象：

  list[0] = new ReadingMatter ("Words and Stuff", "9-082-1090-1");
  list[1] = new Magazine ("Fashion", "318921019", "Mike Dales");
  list[2] = new Book ("Rocks and Minerals", "3-323-0691-2", "Jamie Dawson");
  String[] mainCharacters = {"Lennie","George","Candy"};
  list[3] = new Novel ( "Of Mice and Men", "4-569-2190-1", "John Steinbeck", mainCharacters);
  list[4] = new TextBook ("Java, Java, Java", "3-131-9871-0", "John Smith", true);

改变后的比较：

public int compareTo(Object other)
{
    ReadingMatter temp = (ReadingMatter)other;
    int result = 0;

    if (this.isbn.compareTo(temp.getIsbn()) > 0)
        result = -1;
    else if (this.isbn.compareTo(temp.getIsbn()) < 0)
        result = 1;

    return result;
}

while循环

while(testing)
  {
     testing = false;

     for(int j = 0; j < list.length - 1; j++)
     {
        if (list[j].compareTo(list[j+1]) > 0)
          {
           temp = list[0];
           list[0] = list[1];
           list[1] = temp;

           testing = true;   
          }
     }
  }

是否与带连字符的数字有关？我怎么绕过连字符？

编辑：问题是循环是无限的，if语句总是被使用

Answer 1

问题是你总是切换索引0和1，但检查索引j和j + 1：

if (list[j].compareTo(list[j+1]) > 0)
{
    temp = list[0];
    list[0] = list[1];
    list[1] = temp;

    testing = true;   
}

因此，如果你有一个索引对j，j+1 j {> 1} compareTo传递＆gt; 0，你将获得无限循环。

Answer 2

由于您的条件仅订阅了元素0和1，因此您最终会list[0] < list[1] < list[2]设置testing=true并再次循环。

无限循环

2 个答案: