Question

我正在尝试添加多个按钮来播放专用声音，即按钮1播放声音1，按钮2播放声音2，按钮3播放声音3，依此类推。我尝试过使用以下代码：

import UIKit
import AVFoundation

class ViewController: UIViewController {

var PlaySound = NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource("tea-pot-whistle", ofType: "wav")!)
var Sound1audioPlayer = AVAudioPlayer()
var pianoSound = NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource("wind_1234", ofType: "wav")!)
var Sound2audioPlayer = AVAudioPlayer()
var pianoSound2 = NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource("Evil_Laugh", ofType: "wav")!)
var Sound3audioPlayer = AVAudioPlayer()

@IBOutlet weak var Btn1 : UIButton!
@IBOutlet weak var Btn2 : UIButton!
@IBOutlet weak var Btn3 : UIButton!

@IBAction func likedThis(sender: UIButton) {

    if (Btn1.tag == 1){
        Sound1audioPlayer.play()
    }
    if(Btn2.tag == 2){
        Sound2audioPlayer.play()
    }
    if (Btn3.tag == 3){
        Sound3audioPlayer.play()
    }



   /*
    CFBundleRef mainBundle = CFBundleGetMainBundle();
    CFURLRef soundFileURLRef;
    soundFileURLRef = CFBundleCopyResourceURL(mainBundle, (CFStringRef) @"givewater", CFSTR ("wav"), NULL);
    UInt32 SoundID;
    AudioServicesCreateSystemSoundID(soundFileURLRef, &SoundID);
    AudioServicesPlaySystemSound(SoundID);*/

}


override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.
    Btn1.tag = 1;
    Btn2.tag = 2;
    Btn3.tag = 3;

    Sound1audioPlayer = try! AVAudioPlayer(contentsOfURL: pianoSound)
    Sound2audioPlayer = try! AVAudioPlayer(contentsOfURL: PlaySound)
    Sound3audioPlayer = try! AVAudioPlayer(contentsOfURL: pianoSound2)

    Sound1audioPlayer.prepareToPlay()
    Sound2audioPlayer.prepareToPlay()
    Sound3audioPlayer.prepareToPlay()

}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}


}

此代码播放声音，但根据按下的按钮，它会播放所有三个声音。我是swift的新手，在目标c中我为每个按钮写了每个IBAction。然后我修改了代码以将所有按钮绑定到单个动作，并使用标签来确定按下了哪个按钮。我能用swift进行这种类型的整合吗？任何帮助都会非常感激。

Answer 1

替换你的，

  if (Btn1.tag == 1){
    Sound1audioPlayer.play()
}
if(Btn2.tag == 2){
    Sound2audioPlayer.play()
}
if (Btn3.tag == 3){
    Sound3audioPlayer.play()
}

与

 if (sender.tag == 1){
    Sound1audioPlayer.play()
}
if(sender.tag == 2){
    Sound2audioPlayer.play()
}
if (sender.tag == 3){
    Sound3audioPlayer.play()
}

你应该使用sender.tag !!如果你检查btn.tag，那么每个条件都将成为现实!!

希望这会有所帮助：）

快速播放多个声音

1 个答案: