我创建了一个包含功能得分和top_hit
的弹性搜索查询。此查询将删除重复并返回每个存储桶的前1个记录。
GET employeeid/info/_search
{"size": 0,
"query" : {
"function_score" : {
"query" : {
"match" : {
"employeeID" : "23141A"
}
},
"functions" : [{
"linear" : {
"AcquiredDate" : {
"scale" : "90d",
"decay" : 0.5
}
}
}, {
"filter" : {
"match" : {
"name" : "sorna"
}
},
"boost_factor" : 10
}, {
"filter" : {
"match" : {
"name" : "lingam"
}
},
"boost_factor" : 7
}
],
"boost_mode" : "replace"
}
},
"aggs": {
"duplicateCount": {
"terms": {
"field": "employeehash",
"min_doc_count": 1
},
"aggs": {
"duplicateDocuments": {
"top_hits": {
"size":1
}
}
}
}
}
}
我得到了预期的结果,但问题是我想使用_score
对结果进行排序。
以下是我简单的o / p
{
"key": "567",
"doc_count": 2,
"duplicateDocuments": {
"hits": {
"total": 2,
"max_score": 0.40220365,
"hits": [
{
"_index": "employeeid",
"_type": "info",
"_id": "5",
"_score": 0.40220365,
"_source": {
"name": "John",
"organisation": "google",
"employeeID": "23141A",
"employeehash": "567",
"AcquiredDate": "2016-02-01T07:57:28Z"
}
}
]
}
}
},
{
"key": "102",
"doc_count": 1,
"duplicateDocuments": {
"hits": {
"total": 1,
"max_score": 2.8154256,
"hits": [
{
"_index": "employeeid",
"_type": "info",
"_id": "8",
"_score": 2.8154256,
"_source": {
"name": "lingam",
"organisation": "google",
"employeeID": "23141A",
"employeehash": "102",
"AcquiredDate": "2016-02-01T07:57:28Z"
}
}
]
}
}
}
问题:如何排序_score:desc?
我没有启用groovy所以我不能使用脚本