我正在使用laravel auth根据类型重定向我的用户。但是我被卡住了。我无法根据用户

时间:2016-05-16 12:08:35

标签: php authentication laravel-5

这是我的routes.php文件

    <?php

/*
|--------------------------------------------------------------------------
| Application Routes
|--------------------------------------------------------------------------
|
| Here is where you can register all of the routes for an application.
| It's a breeze. Simply tell Laravel the URIs it should respond to
| and give it the controller to call when that URI is requested.
|
*/

Route::get('/', function () {
    return view('welcome');
});

Route::get('/login', function(){
    return view('auth.login');
});
Route::post('/login', 'Auth\AuthController@authenticate');

Route::get('/home', 'HomeController@index');

这是我的AuthController.php文件

<?php

namespace App\Http\Controllers\Auth;

use App\User;
use Validator;
use App\Http\Controllers\Controller;
use Illuminate\Foundation\Auth\ThrottlesLogins;
use Illuminate\Foundation\Auth\AuthenticatesAndRegistersUsers;
use Auth;

class AuthController extends Controller
{
    /*
    |--------------------------------------------------------------------------
    | Registration & Login Controller
    |--------------------------------------------------------------------------
    |
    | This controller handles the registration of new users, as well as the
    | authentication of existing users. By default, this controller uses
    | a simple trait to add these behaviors. Why don't you explore it?
    |
    */

    use AuthenticatesAndRegistersUsers, ThrottlesLogins;

    /**
     * Where to redirect users after login / registration.
     *
     * @var string
     */
    protected $redirectTo = '/';

    /**
     * Create a new authentication controller instance.
     *
     * @return void
     */
    public function __construct()
    {
        $this->middleware($this->guestMiddleware(), ['except' => 'logout']);
    }

    /**
     * Get a validator for an incoming registration request.
     *
     * @param  array  $data
     * @return \Illuminate\Contracts\Validation\Validator
     */
    protected function validator(array $data)
    {
        return Validator::make($data, [
            'user_name' => 'required|max:255|unique:users',
            'full_name' => 'required|max:255',
            'password' => 'required|min:6|confirmed',
        ]);
    }

    /**
     * Create a new user instance after a valid registration.
     *
     * @param  array  $data
     * @return User
     */
    protected function create(array $data)
    {
        return User::create([
            'user_name' => $data['user_name'],
            'full_name' => $data['full_name'],
            //'password' => bcrypt($data['password']),
            'password' => $data['password'],
        ]);
    }


    //Auth::attempt(['user_name' => $user_name, 'password' => $password])
    public function authenticate()
    {
        if (Auth::attempt($request->all()) {
            var_dump(Auth::user())
            if(Auth::user()->type == 'admin') {
                return "Welcome company admin let's create some user for your company";

                # code...
            } elseif(Auth::user()->type == manager) {

                return "Welcome manager let's manage your coaches";
            }elseif(Auth::user()->type == 'counterman'){
                return "Welcome counter person let's sell some ticket's";
            }else
            {
                return "Welcome online user let's make a relationship with me";
            }
            return "Gonnnaaa";
            //return redirect()->intended('dashboard');
        }else
        {
            return "you are fucked";
        }

    }
}

在我的项目中,我希望根据类型将用户重定向到不同的页面。我尝试以不同的方式实现这一点。最后我尝试在laravel doc中建议使用AuthController中的authenticate方法,但我得到的AuthController不存在错误。我做错了什么,在我的情况下有什么更好的办法?提前致谢 。我没有编辑除AuthController和路由之外的任何东西。

1 个答案:

答案 0 :(得分:1)

如果您不想自己实施新功能,可以创建一个扩展TypeBasedAuthController的新AuthController

然后,您将通过实现调用父postLogin的{​​{1}}方法来修饰其父级。在登录逻辑之后,您可以根据需要更改postLogin属性。

它应该有意义......:)

编辑:如果您想了解有关PHP中装饰器模式的更多信息,请查看this link:)

EDIT2 - 重要:经过另一次深入搜索后,我找到了更好的解决方案。您所要做的就是覆盖this method in your new TypeBasedAuthController

$redirectTo

现在应该很清楚。